Here, given-
homozygous alleles 'a' have a frequency of 0.3.
Also the alleles are in equilibrium in a Hardy-Weinberg population. The frequency of individuals that are homozygous for this allele are= 0.49.
The Hardy-Weinberg equilibrium can be defined as the principle which states that the variation in the genetic makeup of a population remains constant and unchanged till there are no external interferences, influencing the population.
Calculation-
![p + q = 1\\0.3 + q= 1\\q= 1- 0.3\\\\q= 0.7](https://tex.z-dn.net/?f=p%20%2B%20q%20%3D%201%5C%5C0.3%20%2B%20q%3D%201%5C%5Cq%3D%201-%200.3%5C%5C%5C%5Cq%3D%200.7)
Then to find the frequency of the individuals homozygous for this allele the following formula needs to be used-
![p^{2} + 2pq + q^{2} =1](https://tex.z-dn.net/?f=p%5E%7B2%7D%20%2B%202pq%20%2B%20q%5E%7B2%7D%20%3D1)
![p^{2} = dominant homozygous frequency\\2pq= heterozygous frequency\\q^{2} = recessive homozygous frequency\\](https://tex.z-dn.net/?f=p%5E%7B2%7D%20%3D%20dominant%20homozygous%20frequency%5C%5C2pq%3D%20heterozygous%20frequency%5C%5Cq%5E%7B2%7D%20%3D%20recessive%20homozygous%20frequency%5C%5C)
Thus, the individuals homozygous for the allele can be calculated by ![q^{2} = (0.7)^{2} \\= 0.49](https://tex.z-dn.net/?f=q%5E%7B2%7D%20%3D%20%280.7%29%5E%7B2%7D%20%5C%5C%3D%200.49)
Learn more about the Hardy-Weinberg equilibrium here-
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Answer:
Lystrosaurus as known as or translates to 'shovel reptile'.
Lystrosaurus is the only fossils of this creature have only been found in anatartica, India and south Africa.
Explanation:
Cancellous bone is sometimes called a dense bone.
So the answer would be A
if you are talking about both then the first when measures the meters in a high tide and a low tide and the bottom one shows how it has been increasingly rising and lowering