Which expression is equivalent

Mathematics

1 answer:

choli [55]4 years ago

5 0

The first equation is equal to the one in the question.

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What are the exact values of sin(2π3radians) and cos(2π3radians)

deff fn [24]

We know that
2π/3 radians-------> convert to degrees-----> 2*180/3---> 120°
120°=90°+30°

Part a) Find sin(2π/3)
sin(2π/3)=sin (90°+30°)
we know that
sin (A+B)=sin A*cos B+cos A*sin B
so
sin (90°+30°)=sin 90*cos 30+cos 90*sin 30
sin 90=1
cos 30=√3/2
cos 90=0
sin 30=1/2
sin (90°+30°)=1*√3/2+0*1/2-----> √3/2

the answer part a) is
sin(2π/3)=√3/2

Part b) Find cos (2π/3)
cos (2π/3)=cos (90°+30°)
we know that
cos (A+B)=cos A*cos B-sin A*sin B
so
cos (90°+30°)=cos 90*cos 30-sin 90*sin 30
sin 90=1
cos 30=√3/2
cos 90=0
sin 30=1/2
cos (90°+30°)=0*√3/2-1*1/2----> -1/2

the answer part b) is
cos (2π/3)=-1/2

8 0

3 years ago

7 is a factor of which number? 28 16 11 4 4

maw [93]

Answer:

Step-by-step explanation:

28 = 7 x 4

So,

7 is a factor of 28.

6 0

3 years ago

Which of the following is an asymptote of y = sec(x)?

babunello [35]

Answer: option d. x = 3π/2

Solution:

function y = sec(x)

1) y = 1 / cos(x)

2) When cos(x) = 0, 1 / cos(x) is not defined

3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...

4) limit of sec(x) = lim of 1 / cos(x).

When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.

So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).

Answer: 3π/2

The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).