Answer:
(5 - y) ^3 = 125 - 75y + 15y^2 - y^3
Step-by-step explanation:
Binomial expression
1
1. 1
1. 2. 1
1. 3. 3. 1 --------power of 3
( 5 - y) ^3
( 5 - y) (5 - y) (5 - y)
( a + b) ^3 = a^3 + 3a^2b + 3ab^2 + b^3
a = 5
b = -y
( 5 - y) ^2 = ( 5 - y) (5 - y)
= 5( 5 - y) - y(5 - y)
= 25 - 5y - 5y + y^2
=(25-10y+y^2)
( 25 - 10y + y^2)( 5 - y)
= 5(25 - 10y + y^2) - y( 25 - 10y + y^2)
= 125 - 50y + 5y^2 - 25y + 10y^2 - y^3
Collect the like terms
= 125 - 50y - 25y + 5y^2 + 10y^2 - y^3
= 125 - 75y + 15y^2 - y^3
Yes.
27/51-18/34=0
if something minus something is zero, then the 2 numbers subtracting each other are equal. :)
2x + 8y = 5
2/ 24x - 4y = -15
2x + 8y = 5
48x - 8x = -30
+
--------------------------
50x = -25
x = -1/2
2 * -1/2 + 8y = 5
-1 + 8y = 5
8y = 6
y = 6/8
y = 3/4
x = -1/2 y = 3/4
This is true, because there is an infinite amount of real numbers in both, and they are both countably infinite (so these infinities are equal). Hope this helps!
Answer:
The term that can be added to the list so the GCF is 12h3 would be 48h5.
I hope this helped!! :)
