Answer:
The last method (Round 13.76 to 14, round 9.8 to 10, and round 16.415 to 16; since 14 + 10 + 16 = 40 and 40 is close to 39.975, her answer is reasonable.)
Step-by-step explanation:
Option 1 is unreasonable because removing the decimal points just changes the whole problem and claims that Harshini rode her bike 1376 kilometers on Monday and etc., which she did not. Option 2 is unreasonable because not all the numbers are near 20 and should be rounded to their nearest whole numbers instead to find a more accurate estimate. Option 3 is unreasonable for the same reason as option 2, the numbers should be rounded to their nearest whole numbers instead to find a more accurate estimate. Option 4 is reasonable because the numbers are rounded to the nearest whole numbers which makes the estimate more accurate.
Answer:
Ta fácil le quedan 5 kilos :v de que grado es esto._.
Complete Question
The complete question is shown on the uploaded image
Answer:
1 ) The correct option B
2) The correct option is C
3) The correct option is C
4) The correct option is C
Step-by-step explanation:
From the question we are told that
The proportion that own a cell phone is 
The sample size is n = 15
Generally the appropriate distribution for X is mathematically represented as

So

Generally the number students that own a cell phone in a simple random sample of 15 students is mathematically represented as



Generally the standard deviation of the number of students who own a cell phone in a simple random sample of 15 students is mathematically represented as

Where q is mathematically evaluated as





Generally the probability that all students in a simple random sample of 15 students own a cell phone is mathematically represented as

From the combination calculator is 


Answer:
1.
<u>An extraneous solution is a root of a transformed equation that is not a root of the original equation as it was excluded from the domain of the original equation.</u>
It emerges from the process of solving the problem as a equation.
2.I begin like:
The vertical asymptotes will occur at those values of x for which the denominator is equal to zero:
for example:
x² − 4=0
x²= 4
doing square root on both side
x = ±2
Thus, the graph will have vertical asymptotes at x = 2 and x = −2.
To find the horizontal asymptote, the degree of the numerator is one and the degree of the denominator is two.