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3 years ago

71 cards 5 cards in each box 71 ÷5 with leftover How many boxes are needed for all the cards

Mathematics

2 answers:

Allisa [31]3 years ago

8 0

15 boxes are needed because 70÷5=14
with 1 remainder so you will need another box for that one

Fofino [41]3 years ago

7 0

Answer:

15 boxes

Step-by-step explanation:

Because 71 divided by 5 equals to 14.2, you know that you need at least 14 boxes. However, you cannot have 14.2 boxes, because that implies that you have a fifth of a box, which cannot happen. But because each box can only hold up to 5 cards max, you need to get a 15th box for the last card.

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3 years ago

If the sum of $1! + 2! + 3! + \cdots + 49! + 50!$ is divided by $15$, what is the remainder?

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Step-by-step explanation:

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4 years ago

How do you write y+1=4/5(x-3) in standard form?

Rudik [331]

Answer:

The standard form of the given expression is $- (\frac{4}{5})x + y + (\frac{17}{5}) = 0$

Step-by-step explanation:

Here, the given expression is $y + 1 = \frac{4}{5} (x-3)$

Now, the Standard Form of the equation is ax + by + c = 0

Solving this, we get:

$y + 1 = \frac{4}{5} (x-3) \implies y + 1 = (\frac{4}{5})x - \frac{12}{5}$

⇒ $y + 1 - (\frac{4}{5})x + (\frac{12}{5}) = 0$

or, $y - (\frac{4}{5})x + (\frac{12}{5} + 1 )= 0 \implies y - (\frac{4}{5})x + (\frac{12+ 5}{5}) = 0$

⇒ $y - (\frac{4}{5})x + (\frac{17}{5}) = 0$

Hence, the standard form of the given expression is $- (\frac{4}{5})x + y + (\frac{17}{5}) = 0$

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4 years ago

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laila [671]

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So, 0.8 / 0.5 is the answer.

3 0

3 years ago

Read 2 more answers