<span>The parabola opens upward and is symmetric to the y-axis.
Its general form is: . y \;=\;ax^2 + c
Its y-intercept is (0, 10) . . . Hence: . y \;=\;ax^2 + 10
It passes through (200, 100).
We have: . 100 \:=\:a\cdot200^2 + 10 \quad\Rightarrow\quad a \:=\:\frac{9}{4000}
Hence: . y \;=\;\tfrac{9}{4000}x^2 + 10
When x = \pm50,\;\;y \:=\:\tfrac{9}{4000}(50^2) + 10 \:=\:\frac{125}{8}
Therefore, 50 feet from the center, the cable is 15\tfrac{5}{8} feet high.</span>
It would be 60 feet because they are 60 feet apart for all the bases.
we have the following expression
we can simplify it as it follows
then:
Thus, the solution is option b
Answer: h = 6
explanation:
first u get h by itself
4h + 6 = 30
subtract 6 from both sides
4h = 24
divide by 4 on both sides
h = 6