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Mashcka [7]
3 years ago
15

tanji creates a "square, circle" repeating pattern. Kenji creates a "Square, circle, trianglr, cricle" repeating pattern. if bot

h tanji and kenji have 100 shapes in their patterns, which pattern cobtains more circles?
Mathematics
1 answer:
RoseWind [281]3 years ago
3 0

Both tanji & kenji have same number of circles i.e. 50 .

<u>Step-by-step explanation:</u>

Here we have , tanji creates a "square, circle" repeating pattern. Kenji creates a "Square, circle, triangle, circle" repeating pattern. if both tanji and kenji have 100 shapes in their patterns,  . We need to find that which pattern contains more circles .Let's find out :

<u>tanji creates a "square, circle" </u>

it's given that tanji has 100 shapes and he is repeating this pattern . In this pattern circle comes 1 every time out of 2 shapes :

Total number of times circle = \frac{100}{2}(1)

Total number of times circle = 50

<u>Kenji creates a "Square, circle, triangle, circle" </u>

it's given that tanji has 100 shapes and he is repeating this pattern . In this pattern circle comes 2 every time out of 4 shapes :

Total number of times circle = \frac{100}{4}(2)

Total number of times circle = 50

Both tanji & kenji have same number of circles i.e. 50 .

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Nat2105 [25]

Answer:

We conclude that the mean IQ of her students is different from the national average.

Step-by-step explanation:

We are given that the national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15.

The dean of a college want to test whether the mean IQ of her students is different from the national average. For this, she administers IQ tests to her 144 students and calculates a mean score of 113

Let, Null Hypothesis, H_0 : \mu = 100 {means that the mean IQ of her students is same as of national average}

Alternate Hypothesis, H_1 : \mu\neq 100  {means that the mean IQ of her students is different from the national average}

(a) The test statistics that will be used here is One sample z-test statistics;

               T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ N(0,1)

where, Xbar = sample mean score = 113

              s = population standard deviation = 15

             n = sample of students = 144

So, test statistics = \frac{113-100}{\frac{15}{\sqrt{144} } }

                             = 10.4

Now, at 0.05 significance level, the z table gives critical value of 1.96. Since our test statistics is more than the critical value of z which means our test statistics will fall in the rejection region and we have sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean IQ of her students is different from the national average.

3 0
4 years ago
How do i solve m/4+6=3
Ber [7]

\frac{m}{4}  + 6 = 3
\frac{m}{4}  = 3 - 6
\frac{m}{4}  =  - 3
m = ( - 3)(4)
so m=-12
8 0
4 years ago
Steve is collecting toy cars. He already has 100 of them! 42 of them are new, 19 are his favorites; 3 are new and a favorite. St
ZanzabumX [31]

Answer:

42

Step-by-step explanation:

This can be done with a Venn diagram, but I can't draw it here, so I'll explain it.

Of the 42 new ones, 3 are also his favorite. That means there are 39 new that are not favorite.

Of the 19 favorites, 3 are also new, so 16 are favorite but not new.

New but not favorite: 39

Favorite but not new: 16

New and favorite: 3

Total above: 39 + 16 + 3 = 58

He has a grand total of 100 toy cars, so 100 - 58 = 42

42 are neither new nor favorite.

4 0
3 years ago
HELP ME I DON'T UNDERSTAND THIS :(
andriy [413]

Answer:

c

Step-by-step explanation:

Since the figures are similar then the ratios of corresponding sides are equal, that is

\frac{AD}{WZ} = \frac{CD}{YZ} , substitute values

\frac{10}{46} = \frac{5}{YZ} ( cross- multiply )

10YZ = 230 ( divide both sides by 10 )

YZ = 23 → c

3 0
3 years ago
EB = 33, BD = 5x - 10 and ED = 9x + 3. Find x.
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X=11
The triangle equals to 180
Hope this helps!!
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