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s2008m [1.1K]
3 years ago
10

6/15=3/x solve for x

Mathematics
2 answers:
nlexa [21]3 years ago
7 0

Answer: 7.5


Step-by-step explanation:

• Cross multiply : start by multiplying 15 times 3

• You get 45, then you divide 45 by 6

• Therefore, this gives you 7.5

• Check your answer by plugging in 7.5 to x

• Both fractions should equal 0.4, meaning they are equal to each other


denis23 [38]3 years ago
3 0

Answer:15/2


Step-by-step explanation:


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Compute​ P(x) using the binomial probability formula. Then determine whether the normal distribution can be used to estimate thi
stich3 [128]

Answer:

The answers to the questions are;

A) P(X) where x = 12 is equal to 3.55 ×10⁻²

B) P(x) using the normal distribution is given by the probability distribution function and is equal to 3.453 ×10⁻²

C) The calculated probabilities of P(x=12) using the binomial probability formula and the probability distribution function differ by 9.7×10⁻⁴

D) The normal distribution be used to approximate this probability because     a. because np(1-p) %u2265 ⇒ np(1-p) ≥ 10

E) c. the value of fi represents the expected proportion of observation less than or equal to the ith data value.

Step-by-step explanation:

To solve the question, we note that

n = 58

p = 0.3

x = 12

Here we have n·p = 17.4 and n·q = 40.6 both ≥ 5 that is the normal distribution can be used to estimate the probability

A) We are to use the binomial probability formula to find P(X)

Where x = 12, we have P(12) = ₅₈C₁₂×0.3¹²×0.7⁴⁶

= 891794789340×0.000000531441×7.49×10⁻⁸ = 3.55 ×10⁻²

B) Using the standard distribution table we have

the z score for x = 12 given as z = \frac{x-\mu}{\sigma} = -1.55

From the normal distribution table, we have the probability that value is below 12 = .06057 while the normal probability distribution function which gives the probability of a number being 12 is given by

\frac{1}{\sigma\sqrt{2 \pi } } e^{\frac{-(x-\mu)^2}{2\sigma^2} }

where:

σ = Standard deviation = \sqrt{npq} = \sqrt{np(1-p)} = \sqrt{58*0.3*(1-0.3)} = 3.48999

μ = Sample mean = n·p = 58×0.3 =17.4

Therefore the probability density function is \frac{1}{3.49\sqrt{2 \pi } } e^{\frac{-(12-17.4)^2}{2*3.49^2} } = 3.453*10^{-2}

C)  The probabilities differ by 3.55 ×10⁻² -  3.453 ×10⁻² =  9.7×10⁻⁴

D) The normal distribution be used to approximate this probability because     n·p and n·p·(n-p) ≥ 5

E)   f_i represents the area under the curve towards left of the ith data observed in a normally distributed population.

Therefore, the value of fi represents the expected proportion of observation less than or equal to the ith data value  

5 0
2 years ago
Please help!!!! :)))))))))))
LekaFEV [45]
-2 5/12 - 3 2/3 + 1 1/2 = 
- 29/12 - 11/3 + 3/2 =
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7 0
3 years ago
Read 2 more answers
Pls help me solve pls show how you got the answer
Dmitry [639]

Polynomial 1 : x²-x²+4x -2+1 = 4x -1

Polynomial 2 : 3x-x-2x²-2+1 = -2x²+2x-1

Polynomial 3 : 4 -2x+x-x²+x²-x² = -x²-x+4

According to the question,

Polynomial 1+Polynomial2+Polynomial3 + Polynomial4 = 6x

=> 4x -1+ (-2x²+2x-1) +(-x²-x+4) + Polynomial4= 6x

=> -3x²-x+2+Polynomial4= 0

<h2>=> 3x²+x -2= Polynomial4</h2>

OPTION B

6 0
2 years ago
Read 2 more answers
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