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Leviafan [203]
3 years ago
15

A polynomial has zeros x=0, x= -3, X = 4. What are some possible factored equations for this fourth degree polynomial.

Mathematics
1 answer:
kati45 [8]3 years ago
5 0

Answer:

x^{2} (x + 3)(x - 4)

Step-by-step explanation:

You can multiply this out to get the full equations.

It's to the 4th degree so the x on the outside has to be squared to add the fourth degree.

To get other zeros:

x + 3 = 0

x = -3

x - 4 = 0

x = 4

Hope this helped. :0)

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A cone and a sphere both have a radius of 1. If you fill the cone with liquid, and pour it into the sphere, it fits exactly. Wha
PtichkaEL [24]

Answer and Step-by-step explanation:

First, solve for the volume of the sphere, then solve for the height of the cone using the volume of the sphere (which is said to be equal to the volume of the cone) and the radius given.

<u>Volume formula of Sphere</u>

V = \frac{4}{3} \pi r^2

<u>Substitute 1 in for r</u>

\frac{4}{3} \pi (1)^2 = \frac{4}{3} \pi  = 4.189 = Volume

<u>Finding the Height of a Cone</u>

Volume formula for Cone: V = \pi r^2\frac{h}{3}

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<u>Solve for </u><u><em>h</em></u>

Multiply both sides by 3, then divide by pi and r^2.

h = \frac{3V}{\pi r^2}

<u>Plug in the volume and the radius.</u>

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h ≈ 4

<u>4 is approximately the height.</u>

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6 0
3 years ago
Someone please help me
Step2247 [10]

Answer:

20 sq in

Step-by-step explanation:

formula is (base * height)/2 so plug it in:

5*8=40

40/2=20

20 sq in

8 0
1 year ago
How is my graphs line be for this question?
tekilochka [14]
Looking at the table everything is correct if that is what you are asking.
 
3 0
3 years ago
Point M is the midpoint of segment AB.<br> AM=3x+40 and MB=x^2. Find x and AB
Nina [5.8K]

\text{Hello there! :)}

x = 8\\\\AB = 128 \text{ units}

-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-

\text{Since Point M is the midpoint of AB, then:}\\\\AM = MB\\\\

\text{Set the two equations equal to each other:}\\\\3x + 40 = x^{2} \\\\

\text{Move all terms over to one side to simplify more easily:}\\\\0 = x^{2} - 3x - 40

\text{Factor by finding numbers that sum up to -3 and multiply into -40:}\\\\0 = (x - 8)(x + 5)\\\\x = -5, 8

\text{The length of a segment cannot be negative, so choose the positive solution:}\\\\x = 8

\text{Substitute in this value of x into either AM or MB to solve for AB:}

AB = 2(MB)\\\\AB = 2(x^{2} )\\\\AB = 2(8^{2})\\ \\AB = 2(64)\\\\AB = 128 \text{ units}

5 0
3 years ago
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