You need to multiple 7 and 5 or you could just skip the answer
Find the common denominator for both unlike fractions.
EX: 1 2
12 8
The lowest common factor is both fractions is 24. Multiply both denominators to get 24.
Do not forget to multiply the numerators with the number you used to multiply the denominators together.
You do not have to multiply each side by the same number.
Answer:

Step-by-step explanation:
We need to use the properties shown below to solve this:
1. ![\sqrt[n]{x^a} =x^{\frac{a}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Ea%7D%20%3Dx%5E%7B%5Cfrac%7Ba%7D%7Bn%7D%7D)
2. 
3. 
Area of a triangle is given by 1/2 * base * height, so we do that and simplify:

Step-by-step explanation:
So the question is easy ....The thing that you need to do here is ...You should divide area by length....and you will get your answer....
- Area of square = l²
- Area of rectangle = l × b
Area of rectangular parking lot = 7081 m²
length of parking lot = 97 m
Width = ?
Now,
Area = l × b
7081 = 97 × b
7081 / 97 = b
b = 73 m
Hence the width is 73 m....