Question

Evaluate tan60degrees over cos45degrees

Answer 1

Tan(60)/cos(45) = (sin(60)/cos(60))/cos(45)
= ((√3/2)/(1/2))/(√2/2) = (√3)/(√2/2) = (2√3)/(√2)
= ((2√3)(√2))/((√2)(√2)) = (2√6)/2 = √6

If any step doesn't makes sense, hmu!

Answer 2

Answer:

$\sqrt6$

Step-by-step explanation:

We are given that $\frac{tan60^{\circ}}{cos45^{\circ}}$

We have to evaluate tan 60 degrees over cos 45 degrees

We know that $tan 60=\sqrt3$

$cos45=\frac{1}{\sqrt2}$

Substitute the values then we get

$\frac{tan60^{\circ}}{cos45^{\circ}} =\frac{\sqrt3}{\frac{1}{\sqrt2}}$

When a denominator in fraction then the number in the denominator of denominator fraction will convert into multiply

Suppose , we have

$\frac{2}{\frac{2}{3}}=\frac{2\times 3}{2}=3$

Using this rule

$\frac{tan60^{\circ}}{cos45^{\circ}} =\sqrt3\times \sqrt2=\sqrt6$

$\frac{tan60^{\circ}}{cos45^{\circ}} =\sqrt6$

Hence, $\frac{tan60^{\circ}}{cos45^{\circ}} =\sqrt6$