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saul85 [17]
2 years ago
8

Sara owns an exotic pet store. She wants to make sure she has more than a pound of food for every 15 lizards she has in the stor

e. If she currently has 4.25 pounds of food, how many lizards can she have in the store?
Which inequality can be used to solve the problem?
x/15 is less than 4.25
x/15 is greater than 4.25
15x is greater than 4.25
4.25x is less than 15
Mathematics
2 answers:
RSB [31]2 years ago
6 0

Answer:

<u><em>Which inequality can be used to solve the problem? </em></u>

A : x/15 < 4.25

<u><em>Solve the inequality. How can you interpret the solution? </em></u>

C : She can have a maximum of 63 lizards in the store.

Step-by-step explanation:

Edgen answer.

Multiplication and Division Inequalities  Assignment

Writing, Solving, and Interpreting an Inequality

kaheart [24]2 years ago
5 0

Answer:

1- A

2-C

Step-by-step explanation:

i got it on edg and its right

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3 years ago
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There is a L-shaped sidewalk that is 158 meters long. By cutting across the lawn, the
NikAS [45]

Answer:

Each side of the L-shaped sidewalk is 126 m and 32m respectively.

Step-by-step explanation:

Given:

Total length of the sidewalk = 158 meters

Cutting across the lawn the distance = 130 meters

The L-shaped lawn will be treated as a right angled triangle.

So the 130 m distance is the hypotenuse here.

Let one side of the L-shaped lawn be 'x' meter so the another side will be (158-x) meters.

Applying Pythagoras formula.

(Hypotenuse)^2=(height)^2+(base)^2

So,

⇒ (130)^2=x^2 +(158-x)^2

⇒ (130)^2=x^2+(158-x)(158-x)

⇒ 16900=x^2+24964-158x-158x+x^2

⇒ 16900 =2x^2-316x+24964

⇒ 2x^2+316x+24964-16900=0

⇒ 2x^2-316x+8064=0

⇒ x^2-158x+4032=0

Applying quadratic formula;

Quadratic formula : \frac{\pm b \sqrt{b^2-4ac} }{2a} where a=1 and b=-158 and c=4032

So the value of x= 126 and 32.

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7 0
3 years ago
I need help with this problem
alexandr402 [8]

Answer:

4*x^4*y^22

Step-by-step explanation:

Your goal here is to REDUCE the given expression to simplest terms.

One way in which to approach this problem would be to rewrite (2x^2y^10)^3 as:  (2x^2*y^8)*y^2*(2x^2*y^10)^2.

Dividing this rewritten expression by 2x^2*y^8 results in:

y^2(2x^2*y^10)^2.

We now need to raise (2x^2*y^10) to the power 2.  Doing this, we get:

4x^4*y^20.

Multiply this by y^2 (see above):

y^2*4x^4*y^20

The first factor is 4:  4y^2*x^4*y^20.  This is followed by the product of y^2 and y^20:                   4*y^22*x^4

Finally, this should be re-written as

                                    4*x^4*y^22

Another way of doing this problem would involve expanding the numerator fully and then cancelling out like factors:

8*x^6*y^30      4*x^4*y^22

----------------- = ------------------ = 4*x^4*y^22

  2x^2y^8                  1

7 0
2 years ago
Who can help me on this ?
Anna [14]

Answer: 3

Step-by-step explanation:

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2 years ago
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