Consider the inequality -5(x+7)<-10. write an inequality representing the solution for x

Mathematics

1 answer:

Virty [35]2 years ago

6 0

Answer:

$x > 3$

Step-by-step explanation:

$- 5(x + 7) < - 10$

Dividing by - 5

$x + 7 > 10 \\ x > 3$

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Work Shown:

Angle theta is between 0 and pi/2, so this angle is in quadrant Q1.

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Then use the pythagorean trig identity to get

$\sin^2 \theta + \cos^2 \theta = 1\\\\\cos^2 \theta = 1-\sin^2 \theta\\\\\cos \theta = \sqrt{1-\sin^2 \theta} \ \ \ \text{cosine is positive in Q1}\\\\\cos \theta = \sqrt{1-\frac{1}{16}}\\\\\cos \theta = \sqrt{\frac{16}{16}-\frac{1}{16}}\\\\\cos \theta = \sqrt{\frac{16-1}{16}}\\\\\cos \theta = \sqrt{\frac{15}{16}}\\\\\cos \theta = \frac{\sqrt{15}}{\sqrt{16}}\\\\\cos \theta = \frac{\sqrt{15}}{4}\\\\$