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djverab [1.8K]
3 years ago
12

What is log x + log y - 2 log z written as a single logarithm?

Mathematics
1 answer:
Mademuasel [1]3 years ago
3 0

Answer:

D) log (xy/z^2)

Step-by-step explanation:

The given expression is log x + log y - 2 log z

Here we use log rules to simplify this.

Product rule: log x + log y = log (xy)

Quotient rule : log x - log y = log(x/y)

Power rule: log(x^y) = y.log(x)

Using the product rule

log x + log y - 2 log z

= log(xy) - 2 log z

Use the power rule now.

= log(xy) - log z^2

Now we have to use the Quotient rule and simplify.

= log \frac{xy}{z^{2} }

Answer: D) log (xy/z^2)


Thank you.

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The formula for the distance traveled over time t and at an average speed v. v times t. If Amit ran for 40 minutes at a speed of
lorasvet [3.4K]

Answer:

Thus, Amit ran 3.33 KM

calculation needed:

conversion of time (40 minutes to hour)

multiplying velocity  and time (which we got in hours)

Step-by-step explanation:

Given

to calculate the distance: . v times t

that is multiply v with t

where v is average velocity

t is the  time

__________________________________

Given

v = 5 km/hour

time = 40 minutes

since speed is in Km per hour and also we have to find distance in km

lets convert time which in 40 minutes to hour

we know

60 minutes = 1 hour

1 minute = 1/60 hour

40 minutes = 40/60 hour = 2/3 hour

distance = v times t

distance = 5*2/3 = 10/3 = 3 1/3 km = 3.33 km

Thus, Amit ran 3.33 KM

calculation needed:

conversion of time (40 minutes to hour)

multiplying velocity  and time (which we got in hours)

4 0
3 years ago
How do you rationalize the numerator in this problem?
maw [93]

To solve this problem, you have to know these two special factorizations:

x^3-y^3=(x-y)(x^2+xy+y^2)\\ x^3+y^3=(x+y)(x^2-xy+y^2)

Knowing these tells us that if we want to rationalize the numerator. we want to use the top equation to our advantage. Let:

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That tells us that we have:

\frac{x-y}{h}

So, since we have one part of the special factorization, we need to multiply the top and the bottom by the other part, so:

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So, we have:

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That is our rational expression with a rationalized numerator.

Also, you could just mutiply by:

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Either way, our expression is rationalized.

7 0
3 years ago
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