Answer:
If a is 1.. we substitute one in every a in g(a)
4 * 1 + 16
4+ 16 = 20
g(a)= 20
f(20)
-16 + 20 = 4
and 4/4 = 1
so f (g (a)) = a
Step-by-step explanation:
U put two dots on the line to make one
Answer:
Thus, Amit ran 3.33 KM
calculation needed:
conversion of time (40 minutes to hour)
multiplying velocity and time (which we got in hours)
Step-by-step explanation:
Given
to calculate the distance: . v times t
that is multiply v with t
where v is average velocity
t is the time
__________________________________
Given
v = 5 km/hour
time = 40 minutes
since speed is in Km per hour and also we have to find distance in km
lets convert time which in 40 minutes to hour
we know
60 minutes = 1 hour
1 minute = 1/60 hour
40 minutes = 40/60 hour = 2/3 hour
distance = v times t
distance = 5*2/3 = 10/3 = 3 1/3 km = 3.33 km
Thus, Amit ran 3.33 KM
calculation needed:
conversion of time (40 minutes to hour)
multiplying velocity and time (which we got in hours)
To solve this problem, you have to know these two special factorizations:

Knowing these tells us that if we want to rationalize the numerator. we want to use the top equation to our advantage. Let:
![\sqrt[3]{x+h}=x\\ \sqrt[3]{x}=y](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%2Bh%7D%3Dx%5C%5C%20%5Csqrt%5B3%5D%7Bx%7D%3Dy%20)
That tells us that we have:

So, since we have one part of the special factorization, we need to multiply the top and the bottom by the other part, so:

So, we have:
![\frac{x+h-h}{h(\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2})}=\\ \frac{x}{\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2}}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%2Bh-h%7D%7Bh%28%5Csqrt%5B3%5D%7B%28x%2Bh%29%5E2%7D%2B%5Csqrt%5B3%5D%7B%28x%2Bh%29%28x%29%7D%2B%5Csqrt%5B3%5D%7Bx%5E2%7D%29%7D%3D%5C%5C%20%5Cfrac%7Bx%7D%7B%5Csqrt%5B3%5D%7B%28x%2Bh%29%5E2%7D%2B%5Csqrt%5B3%5D%7B%28x%2Bh%29%28x%29%7D%2B%5Csqrt%5B3%5D%7Bx%5E2%7D%7D%20)
That is our rational expression with a rationalized numerator.
Also, you could just mutiply by:
![\frac{1}{\sqrt[3]{x_h}-\sqrt[3]{x}} \text{ to get}\\ \frac{1}{h\sqrt[3]{x+h}-h\sqrt[3]{h}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx_h%7D-%5Csqrt%5B3%5D%7Bx%7D%7D%20%5Ctext%7B%20to%20get%7D%5C%5C%20%5Cfrac%7B1%7D%7Bh%5Csqrt%5B3%5D%7Bx%2Bh%7D-h%5Csqrt%5B3%5D%7Bh%7D%7D%20)
Either way, our expression is rationalized.