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ExtremeBDS [4]
3 years ago
12

Please answer any questions you can pls

Mathematics
1 answer:
astraxan [27]3 years ago
6 0
37. 6r^2

41. B
42. B
44. C
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Please help! Will give brainlist if correct! :(
raketka [301]

Answer:

Rounding can be referred to as a replacement of a number with another number that is equivalent to it. Rounding can be used to shorten a given number without depriving it of its original value. For example, we have to round 56.89. We can round it as replacing it with 57 which is the closest value to 56.

Rounding numbers isn't that difficult task. In fact, it's quite interesting and easy to do. For rounding, all you are required to do is to figure out which decimal place of the number you want to round off. There are different methods to round off numbers. You can round off numbers to Half Up/Down, Round-Up/Down Round Half to Even/Odd, and So on. Anyhow, here, we are concerned with "To What Place You Want to Round Off a Number". This can be illustrated.

To know how rounding calculator works you just have to understand the way the numbers are rounded off to a particular decimal place. Following is a list of the places to which a number can be rounded off: 1. Ones 2. Tens 3. Hundreds 4. Thousands 5. Ten Thousands 6. Millions 7. Tenths (1 decimal place) 8. Hundredths (2 decimal place) 9. Thousandths ( 3 decimal place) 10. Ten Thousandths (4 decimal place) 11. Hundred Thousandths (5 decimal place) 12. Millionths (6 decimal place)

Step-by-step explanation:

3 0
3 years ago
Please help! I need help with this question.
musickatia [10]

Answer:

B

Step-by-step explanation:

the supplement is the angle that will add to the other angle to get 180 degrees. 180-129=51 which is B.

8 0
3 years ago
Which best describes a triangle with side lengths of 3 inches 4 inches and 8 inches
Ivahew [28]

Answer:

A 3 x 4 x 8 inch triangle

Step-by-step explanation:

duh

6 0
4 years ago
Alice searches for her term paper in her filing cabinet, which has several drawers. She knows thatshe left her term paper in dra
katen-ka-za [31]

You made a mistake with the probability p_{j}, which should be p_{i} in the last expression, so to be clear I will state the expression again.

So we want to solve the following:

Conditioned on this event, show that the probability that her paper is in drawer j, is given by:

(1) \frac{p_{j} }{1-d_{i}p_{i}  } , if j \neq i, and

(2) \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i}  } , if j = i.

so we can say:

A is the event that you search drawer i and find nothing,

B is the event that you search drawer i and find the paper,

C_{k}  is the event that the paper is in drawer k, k = 1, ..., n.

this gives us:

P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}

P(A) = 1 - P(B) = 1 - d_{i} p_{i}

Solution to Part (1):

if j \neq i, then P(A \cap C_{j} ) = P(C_{j} ),

this means that

P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)}  = \frac{P(C_{j} )}{P(A)}  = \frac{p_{j} }{1-d_{i}p_{i}  }

as needed so part one is solved.

Solution to Part(2):

so we have now that if j = i, we get that:

P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}

remember that:

P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}

this implies that:

P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )

so we just need to combine the above relations to get:

P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i}  }

as needed so part two is solved.

8 0
4 years ago
Help me please! These are due today.
IrinaVladis [17]

Answer:

{x}^{2}  + 3x

Step-by-step explanation:

1.

Area of shaded region = Area of external rectangle - Area of internal rectangle

= 4x(x + 2) - x(3x + 5) \\  = 4 {x}^{2}  + 8x - 3 {x}^{2}  - 5x \\  = 4 {x}^{2}  - 3 {x}^{2}  + 8x - 5x \\  =  {x}^{2}  + 3x \\

2.

Let the width of the rectangle be x inches.

Therefore, length of the rectangle = (x + 3) inches

A.

Area of rectangle

=(x + 3)\times x\\=x^2 + 3x\\

B.

Width of rectangle = 4 inches

Length of rectangle = 4 + 3 = 7 inches

Area of rectangle = 7*4 = 28 square inches.

6 0
3 years ago
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