Answer:
Below in bold.
Step-by-step explanation:
Nth term an = a1 + d(n - 1) where a1 = term 1 and d = common difference.
Here a1 = 5 and d = 8-5 = 3.
So an = 5 + 3(n - 1)
15th term a15
= 5 + 3(15 - 1)
= 5 + 42
= 47.
Answer:
<h2>-8</h2>
Step-by-step explanation:
![4-3[6-2(4-3)]\\\\Follow\:the\:PEMDAS\:order\:of\:operations\\\\\mathrm{Calculate\:within\:parentheses}\:\left[6-2\left(4-3\right)\right] : 4\\\\=4-3\times\:4\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:3\times\:4\::\quad 12\\=4-12\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:4-12\:\\\\:\quad -8](https://tex.z-dn.net/?f=4-3%5B6-2%284-3%29%5D%5C%5C%5C%5CFollow%5C%3Athe%5C%3APEMDAS%5C%3Aorder%5C%3Aof%5C%3Aoperations%5C%5C%5C%5C%5Cmathrm%7BCalculate%5C%3Awithin%5C%3Aparentheses%7D%5C%3A%5Cleft%5B6-2%5Cleft%284-3%5Cright%29%5Cright%5D%20%3A%204%5C%5C%5C%5C%3D4-3%5Ctimes%5C%3A4%5C%5C%5C%5C%5Cmathrm%7BMultiply%5C%3Aand%5C%3Adivide%5C%3A%5Cleft%28left%5C%3Ato%5C%3Aright%5Cright%29%7D%5C%3A3%5Ctimes%5C%3A4%5C%3A%3A%5Cquad%2012%5C%5C%3D4-12%5C%5C%5C%5C%5Cmathrm%7BAdd%5C%3Aand%5C%3Asubtract%5C%3A%5Cleft%28left%5C%3Ato%5C%3Aright%5Cright%29%7D%5C%3A4-12%5C%3A%5C%5C%5C%5C%3A%5Cquad%20-8)
Answer:
5,6241
Step-by-step explanation:
I have no idea if this is correct but I hope it is. I hope this helps.
