9/10 - 5/10
because the denominators are the same you keep it and just subtract the numerators
=4/10
This can be reduced to 2/5
Total number of units= 3+1
=4
4u=72
1u= 72/4
=18
Cheeseburger= 18x3
=54
Hamburger= 18
Answer:
x = ±25
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
x² = 625
<u>Step 2: Solve for </u><em><u>x</u></em>
- Square root both sides: x = ±25
<u>Step 3: Check</u>
<em>Plug in x into the original equation to verify it's a solution.</em>
x = -25
- Substitute in <em>x</em>: (-25)² = 625
- Exponents: 625 = 625
Here we see that 625 does indeed equal 625.
∴ x = -25 is a solution to the equation.
x = 25
- Substitute in <em>x</em>: 25² = 625
- Exponents: 625 = 625
Here we see that 625 does indeed equal 625.
∴ x = 25 is a solution to the equation.
Answer:
23x-5
Step-by-step explanation:
20x - 2-3 + 3x) in simpilfy is it 23x5
Answers:
Median: The only median is the segment JG
Altitude: There are two altitudes. They are segment JG and KF
Angle Bisector: There is only one angle bisector and it is segment JG
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Explanations:
The median is a segment that goes from a vertex to the midpoint of the opposite side. Only one segment fits this description and it is segment JG
An altitude is a segment that goes from a vertex to the opposite side, and it is perpendicular to the opposite side (perpendicular is shown with square angle markers). Two segments fit this description which are JG and KF. It is possible for a median to also be an altitude. In this case, triangle KJL is an isosceles triangle (KJ = JL)
Angle bisectors cut a given angle into two equal or congruent halves. The segment JG fits this description. It is possible for a segment to be a median, altitude, and angle bisector.
Side Note: the segment EL is neither a median, nor an altitude, nor an angle bisector.