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yaroslaw [1]
3 years ago
10

3 lightships flash simultaneously at 6 00

Mathematics
1 answer:
Finger [1]3 years ago
4 0
------------------------------------------------------------------------------------
Start Time
------------------------------------------------------------------------------------
6.00am

------------------------------------------------------------------------------------
Find LCM of 12, 30, 66
------------------------------------------------------------------------------------
12 = 2² x 3
30 = 2 x 3 x 5
66 = 2 x 3 x 11
LCM = 2² x 3 x 5 x 11
LCM = 660

⇒ The 3 lights will flash simultaneously again 660 sec later

------------------------------------------------------------------------------------
Convert seconds to minutes
------------------------------------------------------------------------------------
660 sec = 11 min 

------------------------------------------------------------------------------------
Calculate the next time the 3 lightships will flash simultaneously again
------------------------------------------------------------------------------------
6.00 am + 11 mins = 6.11 am

------------------------------------------------------------------------------------
Answer: The 3 lightships will flash at 6.11 am again
------------------------------------------------------------------------------------
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Fofino [41]

9/10 - 5/10

because the denominators are the same you keep it and just subtract the numerators

=4/10

This can be reduced to 2/5

6 0
3 years ago
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at a fourth of july barbecue, mr. adams cooked 3 times as many cheeseburgers as hamburgers. if he cooked a total of 72 burgers,
ki77a [65]
Total number of units= 3+1
                                 =4
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6 0
4 years ago
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Solve the equation for x^2=<br> 625
docker41 [41]

Answer:

x = ±25

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Multiple Roots

Step-by-step explanation:

<u>Step 1: Define</u>

x² = 625

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Square root both sides:                    x = ±25

<u>Step 3: Check</u>

<em>Plug in x into the original equation to verify it's a solution.</em>

x = -25

  1. Substitute in <em>x</em>:                    (-25)² = 625
  2. Exponents:                          625 = 625

Here we see that 625 does indeed equal 625.

∴ x = -25 is a solution to the equation.

x = 25

  1. Substitute in <em>x</em>:                    25² = 625
  2. Exponents:                          625 = 625

Here we see that 625 does indeed equal 625.

∴ x = 25 is a solution to the equation.

8 0
3 years ago
Simplify: 20x - 2-3 + 3x)
vovikov84 [41]

Answer:

23x-5

Step-by-step explanation:

20x - 2-3 + 3x) in simpilfy is it 23x5

6 0
3 years ago
4,5,6 I need help on
goldfiish [28.3K]
Answers:

Median: The only median is the segment JG

Altitude: There are two altitudes. They are segment JG and KF

Angle Bisector: There is only one angle bisector and it is segment JG

--------------------------------------------------------------

Explanations:

The median is a segment that goes from a vertex to the midpoint of the opposite side. Only one segment fits this description and it is segment JG

An altitude is a segment that goes from a vertex to the opposite side, and it is perpendicular to the opposite side (perpendicular is shown with square angle markers). Two segments fit this description which are JG and KF. It is possible for a median to also be an altitude. In this case, triangle KJL is an isosceles triangle (KJ = JL)

Angle bisectors cut a given angle into two equal or congruent halves. The segment JG fits this description. It is possible for a segment to be a median, altitude, and angle bisector.

Side Note: the segment EL is neither a median, nor an altitude, nor an angle bisector. 

4 0
3 years ago
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