- The ball land 71.5m away from the base of the cliff.
- The time taken by the ball in the air is 11.79secs
- The maximum height (above the cliff’s edge) that the cannon ball attains is 170.58m
a) To get how far from the base of the cliff does the ball land, we will use the SOH CAH TOA identity.
This shows that the ball land 71.5m away from the base of the cliff.
b) The time the ball used in the air is the time of flight and it is expressed as:
Hence the time taken by the ball in the air is 11.79secs
c) The formula for calculating the maximum height is expressed as:
Hence the maximum height (above the cliff’s edge) that the cannonball attains is 170.58m.
Learn more here: brainly.com/question/15475876
Answer:
Q+D = 65, multiply both sides by 2525Q + 25D = 162525Q + 10D = 950 subtract to get 15D = 675 D = 675/15 = 135/3 = 45 dimes Q = 65-45 = 20 quarters25(20) + 10(45) = 500+450 = 950
For the first on you divide 100÷7=32 so the other one will be 100÷1,000=21
Answer:
The square root of 145.
Step-by-step explanation:
For this problem, make a right triangle between these two points. To solve for distance, use the Pythagorean formula. We know that one side is 8, and the other side is 9, so square 8 and 9 to get 64 plus 81. When you add these together, you get the square root of 145. You cannot further simplify the square root of 145, so that is the distance between the pair of points.