since the diameter of the base of the cylinder is 6 feet, then its radius is half that, or 3 feet.
![\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=9 \end{cases}\implies V=\pi (3)^2(9)\implies V=81\pi](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%5C%5C%5C%5C%0AV%3D%5Cpi%20r%5E2%20h~~%0A%5Cbegin%7Bcases%7D%0Ar%3Dradius%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Ar%3D3%5C%5C%0Ah%3D9%0A%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Cpi%20%283%29%5E2%289%29%5Cimplies%20V%3D81%5Cpi)
If we have two points;
A(x₁,y₁)
B(x₂,y₂)
m=slope
m=(y₂-y₁) / (x₂-x₁)
Therefore:
(6,7)
(9,2)
m=(2-7) / (9-6)=-5/3.
Solution₁= the solpe of the line that passes through the poitns (6,7) and (9,2) is m=-5/3.
(17,9)
(5,29)
m=(29-9) / (5-17)=20/-12=-5/3
Solution ₂: the slope of the line that passes through the parir of points (17,9) and (5,29) is m=-5/3
Therefore, both lines have the same slope.
In the original set of numbers, the median is six
But, if six was added to the set, then the median would be six
So the median wouldn't decrease at all
The value of q(x) is 
The value of r(x) is 
Explanation:
The given expression is 
We need to rewrite the expression in the form of 
Simplifying the expression, we get,

Separating the fractions, we have,

-----------(1)
Now, we shall further simplify the term
, we get,

Common out 5 from the numerator, we have,

Substituting the value
in the equation(1), we get,

Thus, the expression
is in the form of 
Hence, we have,

and
