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Kaylis [27]
4 years ago
12

Answer both questions please

Mathematics
1 answer:
nikklg [1K]4 years ago
5 0
The first answer would be 44. You just need to add all the numbers together. For the second one the formula for area of a trapezoid is a+b/2*h. So you have to add both bases and divide them by 2 and that multiply that by the height. So if you do the math your answer should be 115. I hope this helps love! :) 
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Pls help pls show working brainliest given to clearest answer
myrzilka [38]

Answer:

x_1=\frac{1+\sqrt{61}}{6}\approx1.47,x_2=\frac{1-\sqrt{61}}{6}\approx-1.14

Step-by-step explanation:

To solve a non-factorable quadratic equation in the form of ax^2+bx+c=0, you need to use the quadratic formula where x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}:

3x^2+x-5=0

x=\frac{-1\pm\sqrt{1^2-4(3)(-5)}}{2(3)}

x=\frac{-1\pm\sqrt{1+60}}{6}

x=\frac{-1\pm\sqrt{61}}{6}

Because of the \pm sign, quadratic equations always have two solutions, whether both are real, only one is real, or both are complex (in the form of a+bi where a is the real part and b is the imaginary part where i=\sqrt{-1}). In this case, because the discriminant is positive (defined as b^2-4ac), then there are 2 real solutions.

The solutions are thus x_1=\frac{1+\sqrt{61}}{6}\approx1.47,x_2=\frac{1-\sqrt{61}}{6}\approx-1.14

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3 years ago
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MA_775_DIABLO [31]

it is the last one im pretty sure

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I need helppp on this question
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Answer:

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Step-by-step explanation:

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3 years ago
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Find two positive consecutive integers whose product is 132.
iren2701 [21]
If x is the first integer, then x+1 is the second. x(x+1)=132 or x^2+x-132=0. This factors as (x-11)(x+12)=0. Thus either x=11 or x=-12 
<span>So either 11 and 12 or -12 and -11 will do.</span>
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Step-by-step explanation: there u go

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