3 years ago

Find two positive consecutive integers whose product is 132.

1 answer:

7 0

If x is the first integer, then x+1 is the second. x(x+1)=132 or x^2+x-132=0. This factors as (x-11)(x+12)=0. Thus either x=11 or x=-12
<span>So either 11 and 12 or -12 and -11 will do.</span>

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