Answer this pls be quick!!!
1 answer:
You might be interested in
The mean absolute deviation for the number of hours students practiced the violin is 6.4.
<h3>What is the mean absolute deviation?</h3>
The average absolute deviation of the collected data set is the average of absolute deviations from a center point of the data set.
Given
Students reported practicing violin during the last semester for 45, 38, 52, 58, and 42 hours.
The given data set is;
45, 38, 52, 58, 42
Mean Deviation = Σ|x − μ|/N.
μ = mean, and N = total number of values
|x − μ| = |45 − 47| = 2
|38− 47| = 9
|52− 47| = 5
|58− 47| = 11
|42− 47| = 5
The mean absolute deviation for the number of hours students practiced the violin is;
Hence, the mean absolute deviation for the number of hours students practiced the violin is 6.4.
To know more about mean value click the link given below.
Taking this example into account, we can see that setting the first value equal to 1, we obtain that 
and 
. Using this information, we find that 
. It shows that when x is positive, the succussive terms are increasing.
Referring to that finding, if we set initial value less than zero, which means that we are solving 0.5x+1<0 and taking a number in the interval of the solution, which means x ∈ (- ∞, -20). Setting x=-19, we find that
and x=-40. In the next iteration, 
. In the next iteration, 
. By this way, we find that even if the initial value is less than zero, value of the successive iterations is increasing.
Using the function
and taking the initial value equal to 4, we find that 
and x=-2. In the next iteration, 
. If we continue the iterations we'll see that they are decreasing.
Setting the initial value equal to 2, we find that
and x=0. The next iteration is 
. In this case, the interations are also decreasing.
If we set the initial value equal to 1, we find that
and x=1. In the next iteration, 
and the iterations are decreasing.
Referring to that finding, if we set initial value less than zero, which means that we are solving 0.5x+1<0 and taking a number in the interval of the solution, which means x ∈ (- ∞, -20). Setting x=-19, we find that
Using the function
Setting the initial value equal to 2, we find that
If we set the initial value equal to 1, we find that