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salantis [7]
3 years ago
15

with vertices D(2, 5), E(6, 4), and F(3, 3), is reflected across the line A student determined one of the vertices on the image

to be (2, –5). Evaluate the student’s answer
Mathematics
1 answer:
Nezavi [6.7K]3 years ago
6 0
The vertices of the image reflected over the line y = x are:
D´( 5 , 2 ),  E´( 4, 6 ) and F´( 3, 3 ).
So ( 2, -5 ) is incorrect and it could be incorrectly reflected across over the x-axis.

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Each pound of food C contains 6 ounces of ingredient P and 3 ounces of ingredient Q. Each pound of food D contains 4.5 ounces of
GuDViN [60]
So hmm the food C = 6p + 3q  and the food D = 4.5p + 1.5q

now, if we check how much is the ratios of C/D for each component, then, mixture M = 144p + 60q, must contain the same ratio for each "p" and "q" component

\bf \textit{ratio of "p"}\implies \cfrac{6}{4.5}\implies \cfrac{4}{3}&#10;\\\\\\&#10;\textit{ratio of "q"}\implies \cfrac{3}{1.5}\implies \cfrac{2}{1}

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now the "p" part... ends up as \bf \cfrac{144}{7}\cdot 4\qquad and\qquad \cfrac{144}{7}\cdot 3\implies \cfrac{576}{7}\qquad and\qquad \cfrac{432}{7}

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3 years ago
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The last one, angle D equals to angle T

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3 years ago
The scores of 1000 students on a standardized test were normally distributed with a mean of 50 and a standard deviation of 5. wh
blondinia [14]

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23 students expected to have scores greater than 60.

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60 is 2 standard deviations above the mean.  This translates into a z-score of +2.  According to a table of z-scores, the area under the standard normal curve to the left of z = 2 is 0.9772; that to the right of z = 2 is 1.0000 - 0.9772, or 0.0228.  This 0.0228 represents the probability that a given score is greater than 60.

This fraction (0.0228) of 1000 students comes out to 23 (rounded up from 22.75).

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