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balandron [24]
4 years ago
9

3/4 equals what over 8

Mathematics
2 answers:
ss7ja [257]4 years ago
8 0

Question

3/4 equals what over 8

3/4 = x/8

x = 3 * 8 : 4

x = 6


3/4 = 6/8 is your answer

--------------------------

6/8 semplified =  3/4 (divide both side by 2)

Verdich [7]4 years ago
6 0

You answer will be 6/8.

Because: 3/4=_/8

If you try to figure out how you got 4 to 8 you would divide 8 by 4 to get 2. Now you know to multiply 2 by both sides such as 3*2=6. SO your final answer will be 3/4=6/8

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3 years ago
Raina, Trey, and Ali have a total of $145 in their wallets. Trey has 4 times what Ali has. Raina has $7 more than Ali. How much
miv72 [106K]

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Step-by-step explanation:

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6 0
3 years ago
What’s 45 divided by 14.04
Vladimir79 [104]

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8 0
3 years ago
8/x-5 - 9/x-4 = 5/x^2-9x+20
adelina 88 [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2752942

_______________


Solve the equation:

\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}


Reduce the fractions at the left side so that they have the same denominator:

\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}


Numerators must be equal:

\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}


I hope this helps. =)


Tags:  <em>rational equation fraction solution algebra</em>

7 0
3 years ago
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