Ask question

Ask question

All categories

3 years ago

10

If Mr. arenth wants to put new carpeting in the room shown, how many square feet should he order L= 14ft. W = 6c-8ft. L= 5+3c ft

.

2 answers:

Anton [14]3 years ago

5 0

Answer:

140 sq. ft

Step-by-step explanation:

Given information: L= 14ft. W = 6c-8ft. L= 5+3c ft.

Equate the values of length.

$5+3c=14$

Subtract 5 from both sides.

$3c=9$

Divide both sides by 3.

$c=3$

The value of c is 3.

The width of the carpet is

$W=6c-8$

$W=6(3)-8$

$W=18-8$

$W=10$

The width of the carpet is 10 ft.

The area of a rectangle is

$A=length\times width$

The area of carpet is

$A=14\times 10$

$A=140$

Therefore, Mr. arenth should order carpet of 140 sq. feet carpet.

amid [387]3 years ago

5 0

If you put 5+3c=14 and solve you will get c=3 so then you put 3 in for c for the width equation. you then get 10 ft for the width. if you multiply 10 ft by 14 ft you would get the answer of 140 sq ft

You might be interested in

A relief fund has been set up to collect donations for the families affected by a recent hurricane. A random sample of 400 peopl

Minchanka [31]

Answer: e. (0.35- 0.25)±1.96 √ (0.35)(0.65)/400+ √ (0.35)(0.75)/400

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Theoretical probability of drawing an 'N' tile?

Hitman42 [59]

Answer:

238/1250.

Step-by-step explanation:

7 0

3 years ago

A 20-ounce bag of popcorn costs $2.80. If the unit price stays the same, how much does a 35-ounce bag of popcorn cost?

Wittaler [7]

Answer:

I think the answer is C

4 0

3 years ago

Make x the subject of the following: b = x - 5

nevsk [136]

B=x-5
To get x on its own you have to add 5 to both sides. This gives you:
b+5=x
or
x=b+5

8 0

4 years ago

What value of b will cause the system to have an infinite number of solutions?

irga5000 [103]

b must be equal to -6 for infinitely many solutions for system of equations $y = 6x + b$ and $-3 x+\frac{1}{2} y=-3$

<u>Solution: </u>

Need to calculate value of b so that given system of equations have an infinite number of solutions

$\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}$

Let us bring the equations in same form for sake of simplicity in comparison

$\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}$

Now we have two equations

$\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}$

Let us first see what is requirement for system of equations have an infinite number of solutions

If $a_{1} x+b_{1} y+c_{1}=0$ and $a_{2} x+b_{2} y+c_{2}=0$ are two equation

$\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$ then the given system of equation has no infinitely many solutions.

In our case,

$\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}$

As for infinitely many solutions $\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$

$\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}$

Hence b must be equal to -6 for infinitely many solutions for system of equations $y = 6x + b$ and $-3 x+\frac{1}{2} y=-3$

8 0

3 years ago