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vladimir1956 [14]
3 years ago
9

The volume Vr (in cubic meters) of a spherical balloon with radius r meters is given by =Vr43πr3. The radius Wt (in meters) afte

r t seconds is given by =Wt+7t3. Write a formula for the volume Mt (in cubic meters) of the balloon after t seconds. It is not necessary to simplify.
Mathematics
1 answer:
Arte-miy333 [17]3 years ago
7 0

Answer:

M_t=\frac{1372}{27}\pi t^9

Step-by-step explanation:

We are given that Volume of spherical balloon in cubic meters

V_r=\frac{4}{3}\pir^3

We have to find the value of volume of the balloon after t seconds.

We are given that radius of spherical balloon after t seconds

W_t=7t^3

Substitute the value then we get

M_t=\frac{4}{3}\pi(7t^3)^3

M_t=\frac{1372}{27}\pi t^9

Hence, the volume of spherical balloon is given by the formula

M_t=\frac{1372}{27}\pi t^9

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Which plan to prove ∆ABD ≅ ∆CBD CANNOT be used based on the information in the diagram?
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The plan that cannot be used to prove that the two triangles are congruent based in the given information is: b. ASA.

<h3>How to Prove Two Triangles are Congruent?</h3>

The following theorems can be used to prove that two triangles are congruent to each other:

  • SSS: This theorem proves that two triangles are congruent when there's enough information showing that they have three pairs of sides that are congruent to each other.
  • ASA: This theorem shows that of two corresponding angles of two triangles and a pair of included congruent sides are congruent to each other.
  • SAS: This theorem shows that if two triangles have two pairs of sides and a pair of included angle that are congruent, then both triangles are congruent to each other.

The two triangles only have a pair of corresponding congruent angles, while all three corresponding sides are shown to be congruent to each other.

This means that ASA which requires two pairs of congruent angles, cannot be used to prove that both triangles are congruent.

The answer is: b. ASA.

Learn more about congruent triangles on:

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(HURRY! I'M BEING TIMED)Write the partial fraction decomposition of the rational expression.
Aleonysh [2.5K]

Answer:

The partial fraction decomposition is \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{50}{x + 1}+\frac{-29}{\left(x + 1\right)^{2}}+\frac{-54}{x + 2}.

Step-by-step explanation:

Partial-fraction decomposition is the process of starting with the simplified answer and taking it back apart, of "decomposing" the final expression into its initial polynomial fractions.

To find the partial fraction decomposition of \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}:

First, the form of the partial fraction decomposition is

                                  \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{A}{x + 1}+\frac{B}{\left(x + 1\right)^{2}}+\frac{C}{x + 2}

Write the right-hand side as a single fraction:

                             \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{\left(x + 1\right)^{2} C + \left(x + 1\right) \left(x + 2\right) A + \left(x + 2\right) B}{\left(x + 1\right)^{2} \left(x + 2\right)}

The denominators are equal, so we require the equality of the numerators:

             - 4 x^{2} + 13 x - 12=\left(x + 1\right)^{2} C + \left(x + 1\right) \left(x + 2\right) A + \left(x + 2\right) B

Expand the right-hand side:

           - 4 x^{2} + 13 x - 12=x^{2} A + x^{2} C + 3 x A + x B + 2 x C + 2 A + 2 B + C

The coefficients near the like terms should be equal, so the following system is obtained:

\begin{cases} A + C = -4\\3 A + B + 2 C = 13\\2 A + 2 B + C = -12 \end{cases}

Solving this system, we get that A=50, B=-29, C=-54.

Therefore,

                                  \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{50}{x + 1}+\frac{-29}{\left(x + 1\right)^{2}}+\frac{-54}{x + 2}

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