Each game was $44.99, if she spent a total of 284.97 and we subtract the cost of the console 284.97 - 194.99 = 89.98, since the two games were equally priced we divide 89.98/2 and get $44.98
Answer:
P(B|A)=0.25 , P(A|B) =0.5
Step-by-step explanation:
The question provides the following data:
P(A)= 0.8
P(B)= 0.4
P(A∩B) = 0.2
Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.
To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:
P(B|A) = P(A∩B)/P(A)
= (0.2) / (0.8)
P(B|A)=0.25
To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:
P(A|B) = P(A∩B)/P(B)
= (0.2)/(0.4)
P(A|B) =0.5
The first cube can land in any one of 6 ways.
The second cube can land in any one of 6 ways.
Total number of ways that 2 dice can land = (6 x 6) = 36 ways.
For any of these ways, the sum of the numbers rolled is 9 :
3, 6
4, 5
5, 4
6, 3
There are 4 ways to roll a 9, out of a total of 36 ways that
the dice can land. So the probability of rolling a 9 is
4 / 36 = 1 / 9 = <em>11-1/9 percent</em>
If there are 92 muffins in total and 17 are blueberry, and 23 are cranberry then the remaining muffins (chocolate chip) is 52 muffins.
