Equalizing fractions

Mathematics

1 answer:

dexar [7]3 years ago

7 0

What is the question?

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stiv31 [10]

The Answer Is No Solution!

4 0

3 years ago

Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li

krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

$A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years$

First, let us calculate the decay constant (k)

$75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036$

Next, let us calculate the half-life as follows:

$\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2} \approx 669\ years$

Therefore the half-life is between 600 and 700 years

5 0

3 years ago

Simplify expression 2i(4.5-20i)3i

Margaret [11]

Answer:

-27+120i

Step-by-step explanation:

that is the answer

3 0

3 years ago

Ken grew 4/5 of an inch last year. Sang grew 3/8 of an inch. Who grew more and by how much?

bonufazy [111]

Ken grew .425 of an inch more than sang because 4/5 is .8 and 3/8 is .375 what you do is you take those two numbers and subtract the smaller one from the bigger one and you get .425 and ken had the bigger growth. plz rate me brainliest

7 0

3 years ago

Read 2 more answers

The radius r of a circle can be written as a function of the area A with the following equation: r= sqrt(A/pi) What is the domai

Zepler [3.9K]

The domain of the function is \[A \ge0\] If A is negative we get an imaginary number for the radius. This makes sense because the area of a circle cannot be negative.

7 0

3 years ago