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3 years ago

11/12 4/7 7/8 least comon denuminator

1 answer:

6 0

<span>Rewriting input as fractions if necessary:
3/2, 3/8, 5/6, 3/1

For (2, 8, 6, 1) the least common multiple (LCM) is 24.

Therefore, the least common denominator (LCD) is 24.

Rewriting as equivalent fractions with the LCD:
36/24, 9/24, 20/24, 72/24

</span>

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Let a = 0.9876 and b = 0.9887 with N = 2, calculate the midpoint.

rodikova [14]

Answer:

For a=0.9876 and b=0.9887 mid point will be 0.98815

Step-by-step explanation:

We have given a = 0.9876 and b = 0.9887

And N = 2

We have to find the mid point

For finding mid point we know that formula

Midpoint $=\frac{a+b}{2}$ , here we have given a=0.9876 and b = 0.9887

So midpoint will be $=\frac{0.9876+0.9887}{2}=\frac{1.9763}{2}=0.98815$

So for a=0.9876 and b=0.9887 mid point will be 0.98815

5 0

3 years ago

How many thirds are in 3 2/3

Serga [27]

3= 3 thirds + 3 thirds + 3 thirds = 9 thirds
2/3 = 2 thirds

9 + 2 = 11 thirds. (11/3)

5 0

2 years ago

Find the area of a circle with a diameter of 6. Either enter an exact answer in terms of pi or use 3.14 for pi

ankoles [38]

So it gives you the diameter but you need the radius of the circle to find the area so to find the radius you just divide the diameter by two. the formula for the area of a circle is A=pi*r^2 so you just multiply 3.14 by 3 squared so you just put it in the calculator as A=3.14*3^2 and you get 28.26 hope this helped

4 0

2 years ago

Jose just submitted his resume to a job posting. The posting started thats the job pays $47.588 annually. What would Jose’s mont

Marrrta [24]

Answer:

3965.67 a month

Step-by-step explanation:

presuming you mean $47,588 annually.

47588/12

8 0

3 years ago

( 3 x 2 ) ^ 4 x 3 ^ -3 / 2 ^ 3 x 3 =<br><br> Simplify the exponential expression

Korvikt [17]

Answer:

Step-by-step explanation:

$\frac{(3*2)^4*3^{-3}}{2^3*3}$

we start simplifying by removing the parenthesis

Multiply the exponents inside the the parenthesis

3^4 * 2^4

$\frac{3^4*2^4*3^{-3}}{2^3*3}$

Now we apply exponential property

a^m * a^n = a^ (m+n)

3^4 * 3^-3 = 3^ (4-3) = 3^1

3 or 3^1 are same

$\frac{3^1*2^4}{2^3*3^1}$

3^1 at the top and bottom so we cancel it out

\frac{2^4}{2^3}

we apply log property . a^m / a^n = a^m-n

Now subtract the exponents

2^(4-3) = 2^1 = 2

4 0

3 years ago