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miv72 [106K]
3 years ago
11

Help help help helphelp​

Mathematics
1 answer:
Alla [95]3 years ago
4 0
3(x-1) is your answer
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Mademuasel [1]
I don't think so.........
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3 years ago
Assume that 22 kids have their names (all different) put into a hat. The teacher is drawing 5 names to see who will speak first,
Vinil7 [7]

Answer:

22 to the 5th power

Step-by-step explanation:

Oh and also these are some of the kid's names:

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3 years ago
Please help! I don't understand how to solve this problem
Ilia_Sergeevich [38]

Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

Assuming an uniform distribution, the standard deviation is given by:

S = \sqrt{\frac{(4 - 0)^2}{12}} = 1.1547

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The sample size is found solving for n when the margin of error is of M = 0.006, hence:

M = z\frac{\sigma}{\sqrt{n}}

0.006 = 1.96\frac{1.1547}{\sqrt{n}}

0.006\sqrt{n} = 1.96 \times 1.1547

\sqrt{n} = \frac{1.96 \times 1.1547}{0.006}

(\sqrt{n})^2 = \left(\frac{1.96 \times 1.1547}{0.006}\right)^2

n =  142,282.

A sample of 142,282 should be taken, which is not practical as it is too large of a sample.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0
2 years ago
In the coordinate plane, what is the length of the line segment that connects points at (0, −1) and (−7, −2) ?
kobusy [5.1K]

Answer:

7.07

Step-by-step explanation:

took the test :)

6 0
4 years ago
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