Answer:
- 273 mL of 5%
- 117 mL of 15%
Step-by-step explanation:
Let q represent the quantity of 15% dressing used. Then the amount of 5% dressing is (390 -q). The amount of vinegar in the mix is ...
0.15q + 0.05(390 -q) = 0.08(390)
0.10q = 31.2 -19.5 = 11.7 . . . . . . subtract 0.05(390) and simplify
q = 117 . . . . . . . . . . . . . . . . . . multiply by 10
390-q = 273
The chef should use 273 mL of the first brand (5% vinegar) and 117 mL of the second brand (15% vinegar).
__
<em>Additional comment</em>
You may have noticed that the value of q is (0.08 -0.05)/(0.10 -0.05)×390. The fraction of the mix that is the highest contributor is the ratio of the difference between the mix value and least contributor, divided by the difference between the contributors: (8-5)/(15-5) = 3/10, the fraction that is 15% vinegar. This is the generic solution to mixture problems.
You didn't include how many gallons each container of bleach has, so I'm just going assume one container has a gallon inside. if 5% of one gallon is active Ingredients, and there are 10 gallons, then that's 1,000%. (one gal = 100%. 100x10= 1,000) 5 x 10= 50, so 50% of 1,000% is active ingredients, which can be simplified to 5% anyway, so 5%
Given:
Measure of a cube = 1 unit on each side.
Dimensions of a space 2 units by 3 units by 4 units.
To find:
Number of cubes that can be fit into the given space.
Solution:
The volume of cube is:
Where, a is the side length of cube.
So, the volume of the cube is 1 cubic units.
The volume of the cuboid is:
Where, l is length, w is width and h is height.
Putting , we get
So, the volume of the space is 24 cubic units.
We need to divide the volume of the space by the volume of the cube to find the number of cubes that can be fit into the given space.
Therefore, 24 cubes can be fit into the given space.