Specify Jacob and last name plz because I have absolutely no idea who that is
First one not sure but have a nice day
And good luck!
Answer:
Gentoype of F1: all Bb
Phenotype of F1: black
Genotypes and phenotypes of F2:
1/4 BB - black fur
1/2 Bb - black fur
1/4 bb - brown fur
Explanation:
Black fur (B) is dominant over brown fur (b).
A true breeding black dog will have the genotype BB.
A true breeding brown dog will have the genotype bb.
If both of them are crossed:
BB x bb
F1 progeny: All Bb with Black fur.
At F2:
Bb x Bb
Progeny:
1 BB - black fur
2 Bb - black fur
1 bb - brown fur
<em>Hence:</em>
<em>Gentoype of F1 = all Bb</em>
<em>Phenotype of F1 = black</em>
<em>Genotypes and phenotypes of F2:</em>
<em>1 BB - black fur</em>
<em>2 Bb - black fur</em>
<em>1 bb - brown fur</em>
