Answer:
n=4
Step-by-step explanation:
Given equation: \[\frac{1}{n-4}-\frac{2}{n}=\frac{3}{4-n}\]
Simplifying the Left Hand Side of the equation by taking the LCM of the denominator terms:
\[\frac{n}{n*(n-4)}-\frac{2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]
=> \[\frac{n - 2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]
=> \[\frac{n - 2n + 8}{n*(n-4)}=\frac{3}{4-n}\]
=> \[\frac{8 - n}{n*(n-4)}=\frac{3}{4-n}\]
=> \[(8-n)*(4-n) =n*(n-4)*3\]
=> \[n-8 =3n\]
=> \[2n =8\]
=> n = 4
Base in your question the coordinate is P is 2, PQ has a coordinate of 8 while PR has a coordinate of 12. To find the mid point of each segment you must first find the coordinate of QR which is from 8-12. So the answer will be
PQ = 5, PR = 6, and QR= 10
Answer:
Therefore the results from adding the equation in this system is

Step-by-step explanation:
Given:
Equations as
.......................1
.......................2
To Find :
Result when adding equation 1 and 2 = ?
Solution
On adding equation 1 and 2 the "3y" term will get cancel and the like terms will combine that is add (11x and -4x ) and ( -17 and - 18) as shown below
11x - 3y = -17
-4x + 3y = - 18
-------------------------------------------
7x + 0 = - 35
---------------------------------------------
Therefore the results from adding the equation in this system is
