Answer:
(-1, 4)
Step-by-step explanation:
-5+3/2 = -1
6+ 2/2 = 4
(-1, 4)
QUESTION 1
The given system of equations are:


We equate the two equations to get:




When x=0,

The solution is (0,1)
QUESTION 2
The given equations are:

and

We equate both equations to get:

Group similar terms,



We put x=0 into any of the equations to find y.

The solution is (0,-1).
QUESTION 3
The given equations are:

and

We equate both equations:

Group similar terms:


This is not true.
Hence the system has no solution.
Answer:
5v-10 is not greater than or equal to 5v-6
180= 56+2u+2u
180=56+4u
u= 31