The value of x in the figure is 9.72
<h3>How to determine the value of x?</h3>
The given shape is a triangle, and the value of x can be calculated using the following laws of cosine
a^2 = b^2 + c^2 - 2bc * cos(a)
So, the equation becomes
x^2 = 14^2 + 10^2 - 2 * 14 * 10 * cos(44)
Evaluate the value of cos(44)
x^2 = 14^2 + 10^2 - 2 * 14 * 10 * 0.7193
Evaluate the product
x^2 = 296 - 201.404
Evaluate the difference
x^2 = 94.596
Evaluate the exponent
x = 9.72
Hence, the value of x in the figure is 9.72
Read more about laws of cosine at
brainly.com/question/4372174
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Yes............................
Answer:
13, 17, 19, and 23
Step-by-step explanation:
13+17+19+23=72
If the given differential equation is
then multiply both sides by 
:
The left side is the derivative of a product,
![\dfrac{d}{dx}\left[\sin(x)y\right] = \sec^2(x)](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%5Csin%28x%29y%5Cright%5D%20%3D%20%5Csec%5E2%28x%29)
Integrate both sides with respect to 
, recalling that 
:
![\displaystyle \int \frac{d}{dx}\left[\sin(x)y\right] \, dx = \int \sec^2(x) \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%5Csin%28x%29y%5Cright%5D%20%5C%2C%20dx%20%3D%20%5Cint%20%5Csec%5E2%28x%29%20%5C%2C%20dx)
Solve for 
:
![\boxed{y = \sec(x) + C \csc(x)}which follows from [tex]\tan(x)=\frac{\sin(x)}{\cos(x)}](https://tex.z-dn.net/?f=%5Cboxed%7By%20%3D%20%5Csec%28x%29%20%2B%20C%20%5Ccsc%28x%29%7D%3C%2Fp%3E%3Cp%3Ewhich%20follows%20from%20%5Btex%5D%5Ctan%28x%29%3D%5Cfrac%7B%5Csin%28x%29%7D%7B%5Ccos%28x%29%7D)
.
