The value of the function at t=0 is 9 , 6<x<7 is -t+5, 1<n<2 is 9, for 
is 9.
Given function which is 9 for 0 to 5 , -t+5 for 5 to 8 and 
for 8<t<11.
A) We have to find the function at t=0 which is 9 because it lies between 0<=t<5.
B) In this we have to find the value of the function when x=t lies between 6 and 7. is -t+5.
C) In this we have to find the value of Q(n) when n lies between 1 and 2 and the value becomes 9 because it lies between 0 and 5.
D) In this we have to find the function at when m belongs to 
the value of m lies between 2 and 4 and the value of m square +1 lies between 3 and 5. Hence the value of function at m square plus one is 9.
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Well the square root of a number is a number times its self equaling the number you're getting the square root of. For example:
<span>√ 25
</span>
To get sqrt of 25 we need to find a number times its self that equals 25. Lets try 8.
8 x 8 = 64
Well thats much too high, We'll try a lower number.
4 x 4 = 16
Just a little higher.
5 x 5 = 25
Since 5 times itself equals 25 that makes it the sqrt.
So, the √ 25 is 5.
A^3
a to the power of three
Answer:
170
The ones period consists of the ones, tens, and hundreds digits.
For this case we have that by definition, the equation of the line in the slope-intersection form is given by:
Where:
m: It is the slope of the line
b: It is the cut-off point with the y axis
We have the following points through which the line passes:
We find the slope of the line:
Thus, the equation of the line is of the form:
We substitute one of the points and find b:
Finally, the equation is:
Answer:
