<span>Formula: H(t) = 56t – 16t^2
</span>
H(t) = - 16t^2 + 56t
<span><span>A.
</span>What is the height of the ball after 1 second? H
(1) = 56(1) – 16(1) ^2 = 40 pt.</span>
<span><span>B.
</span>What is the maximum height? X = - (56)/2(- 16) =
1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.</span>
<span><span>C.
</span><span>After how many seconds will it return to the
ground? – 16t^2 + 56t = 0 - 8t =0 t = 0</span></span>
<span><span>-
</span><span>8t (2 + - 7) = 0 2t – 7 = 0 t = 7/2
Ans: 3.5 seconds</span></span>
On the top problem: Angle A and Angle B are a right angle so it equals 90 degrees. If Angle B is 50 degrees that makes Angle A 40 degrees. Angle A and Angle C is a straight line and equals 180 degrees so if Angle A equals 40 degrees that means Angle C equals 140 degrees.
Answer:
1970.5 thousand
Step-by-step explanation:
Given
Vehicle sales in 2009 = 10,002 thousand
Vehicle sales in 2013 = 17,884 thousand
Required
Determine the average rate of change;
From the given parameters, it can be seen that the number of vehicles is a function of year
Let x represent the years and y represent the number of vehicles;
Such that;
The rate of change is calculate as follows;
Hence, the average rate of change is 1970.5 thousand
