Using the information given above, the sampling distribution of the sample proportion of 100-ohm gold-band is 2.
- <em>Sampling distribution of proportion, P = 2% = 0.02 </em>
- <em>Sample size, n = 100</em>
<u>The sampling distribution of the sample proportion can be calculated thus</u>:
- <em>Distribution of sample proportion = np</em>
Distribution of sample proportion = (100 × 0.02) = 2
Therefore, there is a probability that only 2 of the samples will have resistances exceeding 105 ohms.
Learn more : brainly.com/question/18405415
Answer:
2
Step-by-step explanation:
The average rate of change over [2, 8] is the change in the y-values over the change in the x-values.
Answer:
169
Step-by-step explanation:
65 divided by 5 to get 13
and multiply that with 13
like this: 13x13
to get 169
