<span>A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function h = −16t2 + 36t + 5. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball’s maximum height?
A. 2.25 s; 5 ft
B. 1.13 s; 25.25 ft
C. 1.13 s; 27.5 ft
D. 1.13 s; 65.75 ft <====
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Answer:
Step-by-step explanation:
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Answer:
Range: [-2, 2] {y | -2 ≤ y ≤ 2}
Step-by-step explanation:
The given function is y = 2sinx
We have to find the range of the given function.
Since at y-axis sine function has the variance between -1 to 1 so range of y = sinx is [-1, 1]
and if the amplitude of sine function is 2 then sine function will vary from -2 to 2 which implies that range of y = 2 sinx will be [-2, 2]
So range of y = 2sinx is [-2, 2]