Answer:
![9m + 13](https://tex.z-dn.net/?f=9m%20%2B%2013)
Step-by-step explanation:
1. Collect like terms.
![(7m + 2m) + (6 + 7)](https://tex.z-dn.net/?f=%287m%20%2B%202m%29%20%2B%20%286%20%2B%207%29)
2. Simplify.
![9m + 13](https://tex.z-dn.net/?f=9m%20%2B%2013)
There for the answer is, 9m + 13
Answer:
A: -4
B: 4
C: m(x)<h(x) for every x, t.e m(x)>h(x) cann’t be treu for any value of x.
Step-by-step explanation:
I’m not sure what is fubction m. I will suppose it is linear function.
For example m(x)=x/2-2.
Part A: h(4)-m(16)=1/2(4-2)^2 - 16/2-2=2-6=-4
Part B: y-intersection on h(x), we find how is h(0). So h(0)=1/2(0-2)^2=2.
For m(x), m(0)=0/2-2=-2. So their y-intersections are fare away 4. (See photo)
Part C: First we chak if there any intersection between h and m.
1/2(x-2)^2=x/2-2, si we have
x^2-4x+4-x+4=0
X^2-5x+8=0,
D=5^2-4*8=25-32<0, so m and h don’t have intersection, and from graph we can see that for every value of x, m(x) will always be less than h(x).
Photo: blue is h(x), green is m(x)
Answer: The side of square is 36 cm.
Step-by-step explanation:
Since we have given that
The side of a square is 3 cm smaller than one of the sides of a rectangle and 2 cm greater than its other side. Find the side of the square, if the area of square 30 sq. cm less than the area of rectangle.
Let the side of square be 'x'.
Let the length of rectangle be x+3
Let the breadth of rectangle be x-2
So, Area of rectangle - Area of square = 30
![(x+3)(x-2)-x^2=30\\\\x^2+x-6-x^2=30\\\\x-6=30\\\\x=30+6\\\\x=36](https://tex.z-dn.net/?f=%28x%2B3%29%28x-2%29-x%5E2%3D30%5C%5C%5C%5Cx%5E2%2Bx-6-x%5E2%3D30%5C%5C%5C%5Cx-6%3D30%5C%5C%5C%5Cx%3D30%2B6%5C%5C%5C%5Cx%3D36)
Hence, the side of square is 36 cm.
There were 6 packages at $22.00 = $132
There were 7 packages at $18.00 = $126
Answer:
105
Step-by-step explanation:
since its a straight line it would add up to 180 degrees so 52 + 23 + 75 and you need 180 so 180-75 which gives 105 which is the missing angle