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natima [27]
3 years ago
13

Bernardo graphed the amount of money he earned each week mowing lawns. A line graph titled Lawn Mowing Money has weeks on the x-

axis and money on the y-axis. Week 1 was 100 dollars, week 2 was 70 dollars, week 3 was 80 dollars, week 4 was 120 dollars, week 5 was 90 dollars, week 6 was 60 dollars. Between which weeks was the change in money earned the greatest? weeks 1 and 6 weeks 2 and 4 weeks 4 and 6 weeks 1 and 4
Mathematics
2 answers:
Sati [7]3 years ago
6 0

Answer:

My answer was deleted but it was between 4 and 6 weeks

Step-by-step explanation:

OverLord2011 [107]3 years ago
4 0

Answer:

4 and 6

Step-by-step explanation:

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Drag the point A to the location indicated in each scenario to complete each statement.
Art [367]

The graph from which the position of the point <em>A</em> can determined following

the multiplication with a scalar is attached.

Responses:

  • If <em>A</em> is in quadrant I and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant III</u>
  • If A is in quadrant II and is multiplied by a positive scalar, <em>c</em>, then c·A is in <u>quadrant II</u>
  • If <em>A</em> is in quadrant II and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant IV</u>
  • If <em>A</em> is in quadrant III and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant I</u>

<h3>Methods by which the above responses are obtained</h3>

Background information;

The question relates to the coordinate system with the abscissa represent the real number and the ordinate representing the imaginary number.

Solution:

If A is in quadrant I; A = a + b·i

When multiplied by a negative scalar, <em>c</em>, we get;

c·A = c·a + c·b·i

Therefore;

c·a is negative

c·b is negative

  • c·A = c·a + c·b·i is in the <u>quadrant III</u> (third quadrant)

If A is quadrant II, we have;

A = -a + b·i

When multiplied by a positive scalar <em>c</em>, we have;

c·A = c·(-a) + c·b·i = -c·a + c·b·i

-c·a is negative

c·b·i is positive

Therefore;

  • c·A = -c·a + c·b·i is in <u>quadrant II</u>

Multiplying <em>A</em> by negative scalar if <em>A</em> is in quadrant II, we have;

c·A = -c·a + c·b·i

-c·a is positive

c·b·i is negative

Therefore;

c·A = -c·a + c·b·i is in <u>quadrant IV</u>

If A is in quadrant III, we have;

A = a + b·i

a is negative

b is negative

Multiplying <em>A</em> with a negative scalar <em>c</em> gives;

c·A = c·a + c·b·i

c·a is positive

c·b  is positive

Therefore;

  • c·A = c·a + c·b·i is in<u> quadrant I</u>

Learn more about real and imaginary numbers here;

brainly.com/question/5082885

brainly.com/question/13573157

4 0
2 years ago
Of the 168 hours in a​ week, as a full time​ student, you should spend how many hours per week on school​ work?
bonufazy [111]
I like to use 8 hours of school a day so thats 21 a week but all people are different so at most 36 hours a week
6 0
2 years ago
Find the midpoint of A and B where A has coordinates (8,5)<br> and B has coordinates (3, 7).
Mama L [17]

Answer:

Step-by-step explanation:

Average of x-coordinates = (8+3)/2 = 5.5

Average of y-coordinates = (5+7)/2 = 6

Midpoint at (5.5,6)

5 0
3 years ago
Write the smallest 4-digit numeral using 0,2,8, and 7
Sholpan [36]
Should be 0,2,7,8 i dont think you could go any lower
7 0
3 years ago
For the data in the table, tell whether y varies directly with x . If it does, write an equation for the direct variation. x 0,1
kakasveta [241]

Answer:

yes, y varies directly with x.

y=4x is an equation of the Direct Variation

Step-by-step explanation:

x                 y

0                0

1                 4

2                8

3                12

From the above data:

we can say that y varies directly with x.

Direct variation states that if y is expressed as the product of some constant number k and x.

i.e y=kx

Now, let any points from above data x= 2 and y= 8 to calculate the value of k,

8=2k

⇒ k=\frac{8}{2} =4

Therefore, the equation for the direct variation is, y=4x



3 0
3 years ago
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