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garik1379 [7]
3 years ago
14

Can some one please answer this it is due tomorrow and I could use some help thanks!

Mathematics
1 answer:
max2010maxim [7]3 years ago
8 0

Answer:

15.09

Step-by-step explanation:

Hope this helps!

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Find the sum. Express your answer in simplest form.
Marina86 [1]

Answer:

\frac{10x^2+3}{y^2+4}

Step-by-step explanation:

When adding rational numbers, if the denominator is the same you simply keep the denominator (bottom of fraction) as it is and apply the operation given to the numerator ( top of fraction )

So we have \frac{6x^2+5}{y^2+4} +\frac{4x^2-2}{y^2+4} =\frac{(6x^2+5)+(4x^2-2)}{y^2+4}

==> remove parenthesis and apply signs

\frac{x^2+5+4x^2-2}{y^2+4}

==> simplify numerator by combining like terms

\frac{10x^2+3}{y^2+4}

and we are done!

Note:

like terms are terms with the same variable and exponent

An example of like terms are 6x^7 and 3x^7 as they have x as a variable and a power of 7

The like terms being combined here were (6x² and 4x²) and (5 and -2)

7 0
1 year ago
Read 2 more answers
Urgent pls help!
White raven [17]

Answer:

3^(2/15)

Step-by-step explanation:

Ask in comments if you want.

5 0
3 years ago
The quotient of two and five times a number
trasher [3.6K]
Answer: 2 / 5x
Explanation:
8 0
3 years ago
I need help! Will mark Brainliest for full answer!!!
Softa [21]

<u><em>Answer:</em></u>

Part a .............> x = 11

Part b .............> k = 57.2

Part c .............> y = 9.2

<u><em>Explanation:</em></u>

The three problems deal with inverse variation between two variables

An inverse variation relation between two variables means that when one of the variables increases, the other will decrease (and vice versa)

<u>Mathematically, an inverse variation relation is represented as follows:</u>

y = \frac{k}{x}

where x and y are the two variables and k is the constant of variation

<u><em>Now, let's check the givens:</em></u>

<u>Part a:</u>

We are given that y = 3 and k = 33

<u>Substitute in the original relation and solve for x as follows:</u>

y = \frac{k}{x}\\ \\3 = \frac{33}{x}\\ \\x=\frac{33}{3}=11

<u>Part b:</u>

We are given that y = 11 and x = 5.2

<u>Substitute in the original relation and solve for k as follows:</u>

y=\frac{k}{x}\\ \\11=\frac{k}{5.2}\\ \\k=11*5.2=57.2

<u>Part c:</u>

We are given that x=7.8 and k=72

<u>Substitute in the original relation and solve for y as follows:</u>

y=\frac{k}{x}=\frac{72}{7.8}=9.2 to the nearest tenth

Hope this helps :)

6 0
3 years ago
What is the cost of buying 5 kg of cheese worth<br> $9.00 per kg?
topjm [15]
$45

Hope this helps you
6 0
2 years ago
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