Answer:
![P(2643-51< \bar X < 2643+51)= P(2592< \bar X](https://tex.z-dn.net/?f=%20P%282643-51%3C%20%5Cbar%20X%20%3C%202643%2B51%29%3D%20P%282592%3C%20%5Cbar%20X%20%3C2694%29)
And we can use the z scoe formula given by:
![z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=%20z%20%3D%20%5Cfrac%7B%5Cbar%20X%20-%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
And if we find the z score for the limits we got:
![z = \frac{2592-2643}{\frac{368}{\sqrt{44}}}= -0.919](https://tex.z-dn.net/?f=%20z%20%3D%20%5Cfrac%7B2592-2643%7D%7B%5Cfrac%7B368%7D%7B%5Csqrt%7B44%7D%7D%7D%3D%20-0.919)
![z = \frac{2694-2643}{\frac{368}{\sqrt{44}}}= 0.919](https://tex.z-dn.net/?f=%20z%20%3D%20%5Cfrac%7B2694-2643%7D%7B%5Cfrac%7B368%7D%7B%5Csqrt%7B44%7D%7D%7D%3D%200.919)
And this probability is equivalent to:
![P(-0.919](https://tex.z-dn.net/?f=%20P%28-0.919%3CZ%3C0.919%29%20%3D%20P%28Z%3C0.919%29-P%28Z%3C-0.919%29%20%3D%200.821-0.179%3D%200.642)
Step-by-step explanation:
For this case we can define the random variable X as "number of miles between services" and we know the following info given:
![\mu = 2643 , \sigma = 368](https://tex.z-dn.net/?f=%20%5Cmu%20%3D%202643%20%2C%20%5Csigma%20%3D%20368)
The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".
From the central limit theorem we know that the distribution for the sample mean
is given by:
We select a random sample size of n =44. And we want to find this probability:
![P(2643-51< \bar X < 2643+51)= P(2592< \bar X](https://tex.z-dn.net/?f=%20P%282643-51%3C%20%5Cbar%20X%20%3C%202643%2B51%29%3D%20P%282592%3C%20%5Cbar%20X%20%3C2694%29)
And we can use the z scoe formula given by:
![z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=%20z%20%3D%20%5Cfrac%7B%5Cbar%20X%20-%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
And if we find the z score for the limits we got:
![z = \frac{2592-2643}{\frac{368}{\sqrt{44}}}= -0.919](https://tex.z-dn.net/?f=%20z%20%3D%20%5Cfrac%7B2592-2643%7D%7B%5Cfrac%7B368%7D%7B%5Csqrt%7B44%7D%7D%7D%3D%20-0.919)
![z = \frac{2694-2643}{\frac{368}{\sqrt{44}}}= 0.919](https://tex.z-dn.net/?f=%20z%20%3D%20%5Cfrac%7B2694-2643%7D%7B%5Cfrac%7B368%7D%7B%5Csqrt%7B44%7D%7D%7D%3D%200.919)
And this probability is equivalent to:
![P(-0.919](https://tex.z-dn.net/?f=%20P%28-0.919%3CZ%3C0.919%29%20%3D%20P%28Z%3C0.919%29-P%28Z%3C-0.919%29%20%3D%200.821-0.179%3D%200.642)
Given : (ai + 3)(ai - 6)
⇒ (ai)(ai) - 6(ai) + 3(ai) - 18
⇒ a²i² - 3ai - 18
We know that i² = -1
⇒ -a² - 3ai - 18
Option 3 is the Answer
Answer:
For 24 is log base 4 of 2=x. Rewrite log base 4 (2)=x in exponential form using the definition of a logarithm. If x and b are positive real numbers and b does not equal 1, then log b (x)=y is equivalent to b^y=x. 4^x=2 . The answer would be 1/2.... For 27 is 3. For 21 is 3^x=1/3 3^x= 1/3^1 3^x= 3^-1 it is -1.
Answer:
$9
Step-by-step explanation:
20% goes into a 100 5 times, multiply 1.80 *5 to get 9, this is how i got my answer
hope it helps :)