Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
Total students = 1295
Number of women = 714
Percentage of women = 714/1295 x 100 = 55.14%
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Answer: 55.14% of the students are women.
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Answer:
62.5 oz
Step-by-step explanation:
We can use the ratio proportion method:
x:50::6.25:5
x = (50x6.25)/5
OR a more simple method is to do this:
5 gallons of milk require 6.25 oz. How many oz of powder do I need to get 10x that amount? Since 50 is 10x5, you do the same thing for 6.25, and get 62.5
The place value of a certain digit is 10 times bigger than its adjacent digit to the right so the compare to the 5 in the thousands place it is 1000 times bigger than the 5 in the ones place and 10 times bigger than the 5 in the hundreds place