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evablogger [386]
3 years ago
9

Factor:

Mathematics
1 answer:
nekit [7.7K]3 years ago
6 0

Answer:

a) (7\cdot m^{6}+4)\cdot (7\cdot m^{6}-4)

b) (7\cdot a\cdot b^{8}+1)\cdot (7\cdot a\cdot b^{8}-1)

c) a = 0.7\cdot t^{9}

d) There are two possible answers only considering real coefficients:

(i) 16\cdot x^{2}-81 = (4\cdot x +9)\cdot (4\cdot x - 9)

(ii) 14\cdot x^{2}-81 =(\sqrt{14}\cdot x+9)\cdot (\sqrt{14}\cdot x - 9)

e) (a^{3}+4)\cdot (a^{3}-4)

Step-by-step explanation:

Now we proceed to solve each algebraic equation:

a) Factor 49\cdot m^{12}-16

This binomial is of the form a^{2}-b^{2} = (a+b)\cdot (a-b). In this case, we can rewrite and factor the equation below:

49\cdot m ^{12}-16

(7\cdot m^{6})^ 2-4^{2}

(7\cdot m^{6}+4)\cdot (7\cdot m^{6}-4)

b) Factor 49\cdot a^{2}\cdot b^{16}-1

This binomial is of the form a^{2}-b^{2} = (a+b)\cdot (a-b). In this case, we can rewrite and factor the equation below:

49\cdot a^{2}\cdot b^{16}-1

(7\cdot a\cdot b^{8})^{2}-1^{2}

(7\cdot a\cdot b^{8}+1)\cdot (7\cdot a\cdot b^{8}-1)

c) Nicole is factoring 0.49\cdot t^{18}-25 by using the rule a^{2}-b^{2} = (a+b)\cdot (a-b). What will she use for the value of a?

From this rule we find that a^{2} = 0.49\cdot t^{18}, that is:

a^{2} = 0.49\cdot t^{18}

a^{2} = \frac{49}{100}\cdot t^{18}

a = \frac{7}{10}\cdot t^{9}

a = 0.7\cdot t^{9}

d) Which binomial is a difference of squares?

A binomial is a difference of square if and only if a^{2}-b^{2} = (a+b)\cdot (a-b). There are two possible answers only considering real coefficients:

(i) 16\cdot x^{2}-81 = (4\cdot x +9)\cdot (4\cdot x - 9)

(ii) 14\cdot x^{2}-81 =(\sqrt{14}\cdot x+9)\cdot (\sqrt{14}\cdot x - 9)

e) Factor a^{6}-16

This binomial is of the form a^{2}-b^{2} = (a+b)\cdot (a-b). In this case, we can rewrite and factor the equation below:

a^{6}-16

(a^{3})^{2}-4^{2}

(a^{3}+4)\cdot (a^{3}-4)

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