<span>The number of cell phone minutes used by high school seniors follows a normal distribution with a mean of 500 and a standard deviation of 50. what is the probability that a student uses more than 580 minutes?
Given
μ=500
σ=50
X=580
P(x<X)=Z((580-500)/50)=Z(1.6)=0.9452
=>
P(x>X)=1-P(x<X)=1-0.9452=0.0548=5.48%
</span>
Answer:
Ratio of 3/4 I think
Step-by-step explanation:
Because you said for every 3 kiwis there are 4 of something so you would take the number of kiwis over the other number.
So the actual meal was at most 130 dollars they paid minus the 20 dolars tip: 130-20=110 dollars.
it was 5 people: Dolores+5 friends, who presumably all paid the same (buffet).
then we have to divide the 110 among the 5 people: it's 110/5=22
so each of them paid at most 22 dollars:
x (the amount they paid)≤22
Cross section of a sphere is a circle
