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Mademuasel [1]
3 years ago
7

The sine of 58º is equal to the cosine of what angle?

Mathematics
1 answer:
Lady_Fox [76]3 years ago
5 0

Answer:

32

Step-by-step explanation:

The cosine is equal to 90 - the sine angle, so 90-58=32

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Answer:

v = 1/(1+i)

PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493

PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748

PV(G)/PV(T) = 2748/493

{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493

3[1-v^(2n)]/(1-v^n) = 2748/493

Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)

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Step-by-step explanation:

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