Question

In this figure, AB¯¯¯¯¯∥CD¯¯¯¯¯ and m∠1=110°. what is m>5?

Answer 1

Answer: The measure of angle 5 is $110^{\circ}$.

Explanation:

It is given that the AB || CD and the measure of angle 1 is $110^{\circ}$.

If a transversal line intersect two parallel line then all the corresponding angles are equal.

In the given figure the line AB || CD and one line is intersect them which is transversal line.

According to the property of transversal line,

$\angle 1=\angle 5$

$110^{\circ}=\angle 5$

Therefore the measure of angle 5 is  $110^{\circ}$.

Answer 2

Try this solution:

According to the condition AB||CD, it means, m∠1=m∠3=m∠5=m∠7. Using this, m∠5=110°