This kind of exercise can be real drudgery. But it's almost all simple arithmetic, so better you than me. I'll do one of these for you, which will show you how to do the other one.
a). sin · cot / sec
You're supposed to know that [ cotangent = cosine/sine ]
and [ secant = 1/cosine ].
Then the problem becomes
sin · (cos/sin) / (1/cos) = cos²
Aw shucks, I might as well also set up 'b)' for you:
b). cos · csc / tan
You're supposed to know that [ cosecant = 1/sine ]
and [ tangent = sine/cosine ].
Then the problem becomes
cos · (1/sin) / (sin/cos) = (cos/sin)²
Now simply plug in the given values of cos A and sin A .
And may I compliment you on your nail care !
Answer:
Step-by-step explanation:
For this division we can first use factoring of the numerator, then eliminate the common factors.
Factoring the numerator by the term grouping method
removed terms
You need to include the image of the number line for anyone to answer lol
Answer:
53
Step-by-step explanation:
its the same to DAB because it is in the opposite side to the DAB