Draw the 4th set in the pattern

Mathematics

1 answer:

Andrej [43]3 years ago

3 0

It seems as if it adds 2 blocks to the bottom end each time, and 1 to the top.

So, it would be a t-shape with those rules

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What is 47/50 as a percentage?

JulsSmile [24]

The answer to 47/40 as a percentage is 94%

4 0

3 years ago

Please help :) I’m really in need of assistance and would appreciate it.

BaLLatris [955]

Answer:

$D) 0.5x^3y + 4x^2 y^2 - 2xy^3$

Step-by-step explanation:

Set up an equation to model the situation,

$(-0.5xy)(x^2 + 8xy - 4y^2)$

Distribute, multiply each term in the parenthesis with the term outside of the parenthesis. Don't forget the laws of exponents, when one multiplies two exponents, with the same base, then one adds the two exponents. A number with no exponential term is two the first degree meaning that it is to the power of one.

$-0.5x^3 y - 4x^2 y^2 + 2xy^3$

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2 years ago

The table below shows the number of cameras made when an assembly line runs at a constant rate for a certain number of hours. Nu

jeka57 [31]

Computing the rate we get:

$\frac{300}{10}\frac{cameras}{\text{hour}}=30\frac{cameras}{\text{hour}}$

Then, when the assembly line runs at the same rate for 24 hours they will produce:

$24\text{hour}\cdot30\frac{cameras}{\text{hour}}=720\text{ cameras}$

Answer: Option C) 720.

7 0

1 year ago

How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the

miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

$\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}$

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$\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}$

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$\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}$