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Ierofanga [76]
3 years ago
15

Energy is transmitted only in indivisible discrete quantities. True or False

Physics
1 answer:
alex41 [277]3 years ago
5 0

Answer:

False

Explanation:

From the fact that light is emitted in portion, it does not follow that light ray is discrete in structure.

The way Einstein put it was that if a beer is always sold in pint bottles, that does not mean that beer contain of indivisible pint bottles. Yet experiments in which light  knocked electrons out of materials insistently made the point that light is absorbed only in the form of discrete portions. An emitted portion or quantum of light energy retains it's individuality in subsequent events as well.

This concept was first stated by Einstein in 1905. From the heuristic point of view that he developed light is always made up of discrete portions possessing energy and momentum.

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a,c,d I thought these are the true statements about these graph

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HELP ASAP!!!! Which of the following is an example of a hypothesis? A) What will happen if a sugar cube in boiling water? B) I t
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C) If an ice cube is placed into a boiling water, then it will melt in less than 2 minutes.

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When a pitcher throws a baseball, it reaches a top speed of 39 m/s. if the
Aliun [14]

From the calculation, the acceleration of the body is 26m/s^2.

<h3>What is motion under gravity?</h3>

When an object is thrown up or down, the motion of the body is influenced by the gravitational pull on the body.

Now;

Given that;

v = 39 m/s

t = 1.5 s

u = 0 m/s

a = ?

v = u + at

v = at

a = v/t

a = 39 m/s/1.5 s

a = 26m/s^2

Learn more about acceleration:brainly.com/question/12550364

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4 0
2 years ago
A rock is thrown vertically upward with a speed of 18.0 m/s from the roof of a building that is 50.0 m above the ground. Assume
Andreyy89

Answer:

(a) 5.7 s

(b) 39 m/s

Explanation:

(a) u = 18 m/s

At the maximum height, the final velocity of ball is zero. lte teh time taken by the ball to go from 50 m height to maximum height is t.

use first equation of motion.

v = u + g t

0 = 18 - 10 x t

t = 1.8 s

Let the maximum height attained by the ball when it thrown from 50 m height is h'.

Use third equation of motion

v^2 = u^2 + 2 g h'

0 = 18^2 - 2 x 10 x h'

h' = 16.2 m

Total height from the ground H = h + h' = 50 + 16.2 = 76.2 m

Let t' be the time taken by the ball to hit the ground as it falls from maximum height.

use third equation of motion

H = ut + 1/2 x g t'^2

76.2 = 0 + 1/2 x 10 x t'^2

t' = 3.9 s

Total time taken by the ball to hit the ground = T = t + t' = 1.8 + 3.9 = 5.7 s

(b) Let v be the velocity with which the ball strikes the ground.

v^2 = u^2 + 2 g H

v^2 = 0 + 2 x 10 x 76.2

v = 39 m/s

4 0
4 years ago
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