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m_a_m_a [10]
2 years ago
15

When a pitcher throws a baseball, it reaches a top speed of 39 m/s. if the

Physics
1 answer:
Aliun [14]2 years ago
4 0

From the calculation, the acceleration of the body is 26m/s^2.

<h3>What is motion under gravity?</h3>

When an object is thrown up or down, the motion of the body is influenced by the gravitational pull on the body.

Now;

Given that;

v = 39 m/s

t = 1.5 s

u = 0 m/s

a = ?

v = u + at

v = at

a = v/t

a = 39 m/s/1.5 s

a = 26m/s^2

Learn more about acceleration:brainly.com/question/12550364

#SPJ1

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0.55 kg mouse moving E at 60m s or a 900 kg elephant moving E at 0.03m Which has the most momentum?
Ulleksa [173]

Answer:

the mouse

Explanation:

the mouse has a momentum of 33 m kg/s

while the elephant has a momentum of 27 m kg/s

i found this out using p=mv

7 0
3 years ago
Sulfur and nitrogen oxide release into the atmosphere is most responsible for ozone depletion acid precipitation global warming
3241004551 [841]
The answer is acid precipitation 

6 0
3 years ago
A migrating robin flies due north with a speed of 12 m/s relative to the air. The air moves due east with a speed of 6.7 m/s rel
mafiozo [28]

Here it is given that speed of migrating Robin is 12 m/s relative to air

so we can say that

\vec v_{ra} = 12 m/s North

so it will be

Let North direction is along Y axis and East direction is along X axis

\vec v_{ra} = 12\hat j

also it is given that speed of air is 6.7 m/s relative to ground

\vec v_a = 6.7 \hat i

now as we know by the concept of relative motion

\vec v_{ab} = \vec v_a - \vec v_b

\vec v_{ra} = \vec v_r  - \vec v_a

now by rearranging the terms

\vec v_r = \vec v_{ra} + \vec v_a

\vec v_r = 12 \hat j + 6.7 \hat i

now we need to find the speed of Robin which means we need to find the magnitude of its velocity which we found above

So here we will say

v_r = \sqrt{12^2 + 6.7^2}

v_r = 13.7 m/s

so the net speed of Robin with respect to ground will be 13.7 m/s

7 0
3 years ago
A boy throws a ball straight up in the air with an initial velocity of V+3 mls . The ball reaches a maximum height and starts to
eduard

Answer:

Option (b)

Explanation:

Let the ball takes time t to reach the maximum height. The final velocity at maximum height is zero.

Use I equation of motion, we get

V = u + gt

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t = 0.306 s

As the air friction is negligible, so the ball takes same time to reach the hand of boy. Thus the time taken by the ball in air is

T = 2 t = 2 x 0.306 = 0.61 s

7 0
4 years ago
You put a ball on the end of a string. You swing the ball
Sav [38]

Answer:

19.6 ms^{-2}

Explanation:

By the definition of  centripetal acceleration ,

a_c=\frac{V^{2} }{r}

where ,

a =  centripetal acceleration

V= velocity

r =  radius of circle

a_c=\frac{V^{2} }{r}[\\a_c=\frac{5.6^{2} }{1.6} \\=19.6 ms^{-2}

3 0
3 years ago
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