The change in momentum is 5500 kg m/s
Explanation:
The change in momentum of an object is given by
where
m is the mass of the object
v is the final velocity
u is the initial velocity
In this problem, we have:
(mass of the motorcycle)
(final velocity)
(initial velocity)
Therefore, the change in momentum is
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Explanation:
∆x=300 m×2
∆t=1.5 s
v=∆x/∆t → v=2×300/1.5 = 400 m/s
Answer:
ms⁻¹
Explanation:
= diameter of merry-go-round = 4 m
= radius of merry-go-round = 
= 
= 2 m
= moment of inertia = 500 kgm²
= angular velocity of merry-go-round before ryan jumps = 2.0 rad/s
= angular velocity of merry-go-round after ryan jumps = 0 rad/s
= velocity of ryan before jumping onto the merry-go-round
= mass of ryan = 70 kg
Using conservation of angular momentum
ms⁻¹
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Noble gases are not highly reactive
