If the horizontal component of the resultant vector is -4.856 m/s and the vertical component is -9.365 m/s, what is the directio
1 answer:
You might be interested in
Answer:
Star A is closer than Star B
Explanation:
As we know that in parallax method of distance measurement the angle subtended by the star when it covers a distance of one Parsec arc length, it is known as parallax angle
Here we can say
so we have
so here we have
angle subtended by Star A = 1 arc sec
angle subtended by star B = 0.75 arc sec
now we have
distance for star A is given as
distance of star B is given as
So star A is closer than star B
Answer:
the lowest possible frequency of the emitted tone is 404.79 Hz
Explanation:
Given the data in the question;
S₁ ← 5.50 m → L
↑
2.20 m
↓
S₂
We know that, the condition for destructive interference is;
Δr = ( 2m + ) × λ
where m = 0, 1, 2, 3 .......
Path difference between the two sound waves from the two speakers is;
Δr = √( 5.50² + 2.20² ) - 5.50
Δr = 5.92368 - 5.50
Δr = 0.42368 m
v = f × λ
f = ( 2m + )v / Δr
m = 0, 1, 2, 3, ....
Now, for the lowest possible frequency, let m be 0
so
f = ( 0 + )v / Δr
f = (v) / Δr
we know that speed of sound in air v = 343 m/s
so we substitute
f = (343) / 0.42368
f = 171.5 / 0.42368
f = 404.79 Hz
Therefore, the lowest possible frequency of the emitted tone is 404.79 Hz
Answer:
λ = 5.734 x 10⁻⁷ m = 573.4 nm
Explanation:
The formula of the Young's Double Slit experiment is given as follows:
where,
λ = wavelength = ?
L = distance between screen and slits = 8.61 m
d = slit spacing = 1.09 mm = 0.00109 m
Δx = distance between consecutive bright fringes = = 0.00453 m
Therefore,
<u>λ = 5.734 x 10⁻⁷ m = 573.4 nm</u>